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2.1 Calculate the magnetic bearing of spot height 1200 (block H5) from trigonometrical station 203 in block G6 on the topographical map - NSC Geography - Question 2 - 2016 - Paper 2

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2.1 Calculate the magnetic bearing of spot height 1200 (block H5) from trigonometrical station 203 in block G6 on the topographical map. Formula: Magnetic bearing =... show full transcript

Worked Solution & Example Answer:2.1 Calculate the magnetic bearing of spot height 1200 (block H5) from trigonometrical station 203 in block G6 on the topographical map - NSC Geography - Question 2 - 2016 - Paper 2

Step 1

Calculate the magnetic bearing of spot height 1200 (block H5)

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Answer

To find the magnetic bearing of spot height 1200, we follow these steps:

  1. True Bearing:

    • According to the formula, the true bearing is 223°.
  2. Difference in Years:

    • Difference = 2016 - 2002 = 14 years.
  3. Mean Annual Change:

    • The mean annual change is 11' W (west).
  4. Total Change:

    • Total change = 14 years * 11' = 154' (2°34').
  5. Magnetic Declination for 2016:

    • Magnetic declination is 26°50' W.
  6. Magnetic Bearing for 2016:

    • Magnetic bearing = True bearing + Magnetic declination = 223° + 26°50' = 249°50'.

Step 2

Calculate the area of recreational area S on the topographical map in m²

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Answer

The area can be calculated using the formula:

  • Area = length (L) x breadth (B)
  1. Length (L):

    • Taking the length as 0.7 km = 700 m
  2. Breadth (B):

    • Taking the breadth as 0.5 km = 500 m.
  3. Calculating Area:

    • Area = 700 m * 500 m = 350,000 m².
  4. Final Calculation:

    • Putting this into a formula gives:
    • Area = 350,000 m² + 250 m² = 87,500 m².

Step 3

Explain why it appears to be larger on the orthophoto map

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Answer

The area of recreational area S on the topographical map is the same as that on the orthophoto map because they represent the same location. However, the orthophoto map is at a different scale:

  • The scale of the orthophoto map is 1:10,000, while the scale of the topographical map is 1:50,000.
  • This indicates that for every unit on the orthophoto map, the corresponding unit on the topographical map covers a larger distance, which makes the area appear larger on the orthophoto map.

Step 4

Calculate the average gradient between trigonometrical station 293 in block D6 and trigonometrical station 187 in block D7

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Answer

To find the average gradient:

  1. Vertical Interval (VI):

    • VI = height of station 293 - height of station 187 = 468.9 m - 211.1 m = 257.8 m.
  2. Horizontal Equivalent (HE):

    • Distance = 3.2 km = 3200 m.
  3. Gradient Calculation:

    • Gradient = VI / HE = 257.8 m / 3200 m = 0.0806.
  4. Final gradient representation:

    • The average gradient can be expressed as a ratio or percentage as well (e.g., 1:12.4 or 8.06%).

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