5.1.1 Write down the line number of any line of code from the provided code segment above that implements the following:
(a) Initialisation
(b) Looping
5.1.2 What will be the value of iCounter after the above code has been executed?
NOTE: Assume that all the variables are declared correctly and there are no errors in the code - NSC Information Technology - Question 5 - 2023 - Paper 2
Question 5
5.1.1 Write down the line number of any line of code from the provided code segment above that implements the following:
(a) Initialisation
(b) Looping
5.1.2 What ... show full transcript
Worked Solution & Example Answer:5.1.1 Write down the line number of any line of code from the provided code segment above that implements the following:
(a) Initialisation
(b) Looping
5.1.2 What will be the value of iCounter after the above code has been executed?
NOTE: Assume that all the variables are declared correctly and there are no errors in the code - NSC Information Technology - Question 5 - 2023 - Paper 2
Step 1
Write down the line number of any line of code that implements Initialisation
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Answer
Line 1 (iCounter := 0)
Step 2
Write down the line number of any line of code that implements Looping
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Answer
Line 4 (sLine := '')
Step 3
What will be the value of iCounter after the above code has been executed?
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Answer
The value of iCounter after execution will be 15, as it is incremented 15 times (3 for the outer loop and 5 for the inner loop).
Step 4
Provide the output of the program after the code above has been executed.
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Answer
The output of the program will be a single line consisting of 15 asterisks: '*****'.
Step 5
Rewrite the second loop (for iCol := 1 to 5 do) as a conditional loop.
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Answer
Using a conditional loop, it could be expressed as:
iCol := 1;
while iCol <= 5 do
begin
inc(iCol);
end;
This loop will continue to execute as long as iCol is less than or equal to 5.
