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1.1 Various options are provided as possible answers to the following questions - NSC Life Sciences - Question 1 - 2016 - Paper 2

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1.1 Various options are provided as possible answers to the following questions. Choose the answer and write only the letter (A to D) next to the question number in ... show full transcript

Worked Solution & Example Answer:1.1 Various options are provided as possible answers to the following questions - NSC Life Sciences - Question 1 - 2016 - Paper 2

Step 1

1.1.1 When a cell divides by meiosis it results in ...

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When a cell divides by meiosis, it results in four haploid gametes. This process reduces the chromosome number by half and ensures genetic diversity.

Step 2

1.1.2 Individuals of the same species may show genetic variation due to ...

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Individuals of the same species may show genetic variation due to meiosis, mutations, random mating and random fertilisation. Each of these factors contributes to the variability in offspring.

Step 3

1.1.3 The structure above is involved in the process of ...

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The structure above (tRNA) is primarily involved in the process of translation, where it brings amino acids to the ribosome for protein synthesis.

Step 4

1.1.4 Molecule X represents ...

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Molecule X represents an amino acid, which is the building block of proteins.

Step 5

1.2.1 A genetic cross involving two different characteristics.

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Dihybrid.

Step 6

1.2.2 The variety of life forms that exist on Earth.

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Biodiversity.

Step 7

1.2.3 The opening in the skull through which the spinal cord enters.

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Foramen magnum.

Step 8

1.2.4 A group of organisms of the same species living in the same habitat at the same time.

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Population.

Step 9

1.2.5 A testable statement that can be accepted or rejected.

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Hypothesis.

Step 10

1.2.6 A genetic disorder resulting in the non-production of the clotting factor in blood.

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Haemophilia.

Step 11

1.2.7 Total disappearance of a species from Earth.

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Extinction.

Step 12

1.2.8 A segment of a chromosome that codes for a particular characteristic.

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Gene.

Step 13

1.2.9 The ability of an organism to walk on two legs.

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Bipedalism.

Step 14

1.3.1 Which TWO babies (from X, Y and Z) were swopped?

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Babies Y and Z were swopped based on the blood group incompatibilities.

Step 15

1.3.2 Give the surnames of the biological parents of the two babies that were swopped.

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Y - Tau; Z - Chaka.

Step 16

1.3.3 Give the possible genotype(s) of Mr Pule that could have produced baby X.

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Mr Pule's possible genotypes that could produce baby X (blood group B) include IBi or IBIB.

Step 17

1.4.1 How many of the following are present in the karyotype: (a) Chromosomes

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(a) 46 chromosomes.

Step 18

1.4.1 (b) Autosomes

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(b) 44 autosomes.

Step 19

1.4.1 (c) Gonosomes

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(c) 2 gonosomes.

Step 20

1.4.2 How many chromosomes would be present in the gametes produced by this individual?

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This individual would have 23 chromosomes in their gametes, as gametes are haploid.

Step 21

1.4.3 Is the karyotype in the diagram that of a male or a female?

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The karyotype is that of a male, as indicated by the presence of XY chromosomes.

Step 22

1.5.1 Which phase is represented in: (a) Diagram 1

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(a) Diagram 1 represents Prophase I.

Step 23

1.5.1 (b) Diagram 2

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(b) Diagram 2 represents Metaphase II.

Step 24

1.5.2 Provide labels for: (A)

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(A) Centriole.

Step 25

1.5.2 (B)

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(B) Nuclear membrane.

Step 26

1.5.2 (C)

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(C) Homologous pair/Bivalent.

Step 27

1.5.3 Give the functions of the parts labelled: (A)

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(A) Forms spindle fibres during cell division.

Step 28

1.5.3 (B)

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(B) Carries genetic/hereditary material.

Step 29

1.5.4 Are the cells in Diagram 2 haploid or diploid?

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The cells in Diagram 2 are haploid.

Step 30

1.5.5 Name the process that would have caused variation in structure D.

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The process that would have caused variation in structure D is crossing over.

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