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3.1 Staff at public schools are required to adhere to stipulated percentages or fractions related to the total number of weekly periods based on their post level - NSC Mathematical Literacy - Question 3 - 2024 - Paper 1

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3.1 Staff at public schools are required to adhere to stipulated percentages or fractions related to the total number of weekly periods based on their post level.... show full transcript

Worked Solution & Example Answer:3.1 Staff at public schools are required to adhere to stipulated percentages or fractions related to the total number of weekly periods based on their post level - NSC Mathematical Literacy - Question 3 - 2024 - Paper 1

Step 1

3.1.1 Determine the number of staff members at Woodhill SS.

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Answer

To find the number of staff members at Woodhill SS, we observe the given timetables. The number of periods taught by each member should add up to the total periods, which are 40. Counting the numbers provided: the deputy principal's periods (D) and the value of 3 for the three other posts gives us the total staff summary:

(3 + 3 + D + 3 = 40)

This gives: [ D + 9 = 40 ] [ D = 31 ] Thus, there are 4 staff members at Woodhill SS.

Step 2

3.1.2 Write down the modal number of periods per week for Moloto PS.

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Answer

The mode is the number that appears most frequently in a set. For Moloto PS, the periods are:

[3, 9, 10, 10, 10, 11, 12, 15, 15, 15, 15, 18, 19, 21, 23, 29, 29]

The mode is 10, as it appears three times.

Step 3

3.1.3 Calculate missing value D.

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Answer

As computed in step 3.1.1, using the total periods equation:

[ D + 9 = 40 ] [ D = 31 ]

The value of D, representing the duties of the deputy principal, is 31 periods.

Step 4

3.1.4 Justify Ina’s statement with calculations.

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Answer

First, let's find the mean and median of the periods taught at Woodhill SS. The periods are:

[3, 3, 31, 3]

The mean is calculated as: [ \text{Mean} = \frac{3 + 3 + 31 + 3}{4} = \frac{40}{4} = 10 ]

For the median, arranging values results in: [3, 3, 3, 31]

The median, being the average of the two middle values, will be: [ \text{Median} = \frac{3 + 3}{2} = 3 ]

Thus, the median is lower than the mean, which confirms that the median is a more reliable measure of central tendency given that it is less impacted by extreme values.

Step 5

3.1.5 Determine, as a fraction, the probability of randomly selecting a staff member at Moloto PS who teaches 29 or more periods per week.

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Answer

To determine this probability, we first note the total number of staff (which is 16) and then count how many teach 29 or more periods. In the list, we see:

  • Staff members teaching 29 periods: 2.

Thus, the fraction is given by: [ P = \frac{2}{16} = \frac{1}{8} ]

Step 6

3.2.1 (a) Name the type of graph shown on the ANSWER SHEET.

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Answer

The graph shown on the ANSWER SHEET is a scatter plot. This type of graph displays values for typically two variables for a set of data.

Step 7

3.2.1 (b) Calculate the range of the percentages achieved for Task 2.

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Answer

To find the range, we subtract the smallest percentage from the largest percentage in Task 2. The highest value is 81, and the lowest is 15. Therefore, the range is:

[ \text{Range} = 81 - 15 = 66 ]

Step 8

3.2.1 (c) Identify the learner whose marks for both tasks can be classified as an outlier. Give a reason for your answer.

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Answer

The learner whose marks can be classified as an outlier is Learner H, who scored significantly lower in Task 2 (15) compared to other learners. This score stands out when compared with the rest.

Step 9

3.2.2 Verify, showing all calculations, whether this teacher’s claim is VALID.

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Answer

We're told the mean for Task 1 is 66.7%. First, let's calculate the mean for Task 2:

[ \text{Mean (Task 2)} = \frac{53 + 69 + 53 + 49 + 50 + 47 + 61 + 15 + 47 + 81}{10} = \frac{ 510 }{10} = 51 ]

Now, we find the difference between these two means:

[ \text{Difference} = 66.7 - 51 = 15.7 ]

Since 15.7 is not less than 15, the teacher's claim is INVALID.

Step 10

3.2.3 Plotting the results of Learner K and L for both tasks.

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Answer

Learner K achieved 78 in Task 1 and 36 in Task 2. Learner L achieved 79 in Task 1 and 45 in Task 2. The data points for plotting would be:

  • K: (78, 36)
  • L: (79, 45)

These points should be clearly labeled on the graph.

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