NSC Mathematical Literacy Classifying and organising data: Use TABLE 3 above to answer the

Use TABLE 3 above to answer the questions that follow - NSC Mathematical Literacy - Question 3 - 2017 - Paper 2

Question 3

Use TABLE 3 above to answer the questions that follow. 3.1.1 During 2015 the number of black females was estimated to be 41,1% of the total South African population... show full transcript

Worked Solution & Example Answer:Use TABLE 3 above to answer the questions that follow - NSC Mathematical Literacy - Question 3 - 2017 - Paper 2

Step 1

3.1.1 During 2015 the number of black females was estimated to be 41,1% of the total South African population. Determine the estimated total South African population (rounded off to the nearest 100) for 2015.

96%

114 rated

Answer

To calculate the total South African population for 2015, use the provided percentage of black females: 41.1% of the total population is equal to 22,574,500.

Let the total population be denoted as P:

$ext{Black females} = 0.411 imes P$

So,

$P = \frac{22,574,500}{0.411} \approx 54,925,800$

Rounded to the nearest 100, the total population is 54,925,800.

Step 2

3.1.2 The total estimated population of SA during 2016 was 95 008 900. If a person was randomly chosen in 2016, determine the probability that the person would be the following: (a) a white female

99%

104 rated

Answer

To find the probability of choosing a white female from the total population, refer to the number of white females in 2016:

White females in 2016 = 3,325,100.

Thus, the probability is:

$P(\text{White female}) = \frac{3,325,100}{95,008,900} \approx 0.0350 \text{ or } 3.5\%$

Step 3

(b) a male

96%

101 rated

Answer

First, determine the number of males in 2016. The total population is 95,008,900, and we can find the number of females by adding the female populations from all races.

Total females in 2016 = 28,529,100 (given).

Therefore, the number of males is:

$P(\text{Males}) = 95,008,900 - 28,529,100 = 66,479,800$

Now, the probability of randomly choosing a male is:

$P(\text{Male}) = \frac{66,479,800}{95,008,900} \approx 0.6995 \text{ or } 69.95\%$

Step 4

3.1.3 Show, using calculations, that in any TWO consecutive years the Indian/Asian female percentage (rounded off to ONE decimal place) remained the same.

98%

120 rated

Answer

From the table, the Indian/Asian female proportions are as follows:

2014: Indian/Asian percentage = 2.4%
2015: Indian/Asian percentage = 2.4%

Calculation:

$\frac{673,700}{28,703,700} \times 100 \approx 2.4\%$

$\frac{664,900}{28,529,100} \times 100 \approx 2.4\%$

Thus, the percentage remained consistent at 2.4% for both years.

Use TABLE 3 above to answer the questions that follow - NSC Mathematical Literacy - Question 3 - 2017 - Paper 2

Worked Solution & Example Answer:Use TABLE 3 above to answer the questions that follow - NSC Mathematical Literacy - Question 3 - 2017 - Paper 2

3.1.1 During 2015 the number of black females was estimated to be 41,1% of the total South African population. Determine the estimated total South African population (rounded off to the nearest 100) for 2015.

3.1.2 The total estimated population of SA during 2016 was 95 008 900. If a person was randomly chosen in 2016, determine the probability that the person would be the following: (a) a white female

(b) a male

3.1.3 Show, using calculations, that in any TWO consecutive years the Indian/Asian female percentage (rounded off to ONE decimal place) remained the same.

Join the NSC students using SimpleStudy...