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Anda is a teacher in Zambia - NSC Mathematical Literacy - Question 4 - 2024 - Paper 2

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Anda is a teacher in Zambia. ANNEXURE D shows a detailed layout plan of the school building where he teaches. Use the information in ANNEXURE D to answer the questi... show full transcript

Worked Solution & Example Answer:Anda is a teacher in Zambia - NSC Mathematical Literacy - Question 4 - 2024 - Paper 2

Step 1

4.1.1 Write down, in simplified form, the ratio of the number of single doors to the number of double doors on the school layout plan.

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Answer

From the layout plan, if there are 3 single doors and 1 double door, the ratio is:

Ratio=Number of single doorsNumber of double doors=31=3:1\text{Ratio} = \frac{\text{Number of single doors}}{\text{Number of double doors}} = \frac{3}{1} = 3:1

Step 2

4.1.2 Name the rooms that have TWO double doors and ONE single door.

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Answer

The rooms with TWO double doors are 'Computer Lab' and 'Reading Room'. The room with ONE single door is 'Classroom 1'.

Step 3

4.1.3 State ONE feature that indicates that the school has more than one level.

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Answer

One feature indicating that the school has more than one level is the presence of a staircase in the layout plan.

Step 4

4.1.4 During an evacuation drill, Anda took the following route: - Exited the room and turned left into the hallway - Went straight past three single doors on the left and a fire extinguisher on the right. - Turned right at the end of that hallway - Passed two rooms each having a double door - Then used the 'Exit to use in case of fire' Determine the room from which Anda exited during the evacuation drill.

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Answer

Anda exited the room named 'Laboratory' during the evacuation drill.

Step 5

4.1.5 Verify, showing all calculations, if the claim is VALID.

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Answer

To calculate the total area of the laboratory:

  • Area = Length × Width
  • Length = 11 m = 11000 mm, Width = 7 m = 7000 mm

Area=11000 mm×7000 mm=77,000,000 mm2\text{Area} = 11000 \text{ mm} \times 7000 \text{ mm} = 77,000,000 \text{ mm}^2

Now, convert the area from mm² to m²:

Area=77,000,0001,000,000=77 m2\text{Area} = \frac{77,000,000}{1,000,000} = 77 \text{ m}^2

Each tile covers an area of Area of tile=600 mm×600 mm=360,000 mm2=0.36 m2\text{Area of tile} = 600 \text{ mm} \times 600 \text{ mm} = 360,000 \text{ mm}^2 = 0.36 \text{ m}^2

Number of tiles needed:

Number of tiles=77 m20.36 m2214.44 tiles\text{Number of tiles} = \frac{77 \text{ m}^2}{0.36 \text{ m}^2} \approx 214.44 \text{ tiles}

Thus, number of boxes needed:

Boxes needed=214.44542.89 boxes\text{Boxes needed} = \frac{214.44}{5} \approx 42.89 \text{ boxes}

Hence, the claim of needing 40 boxes is INVALID since approximately 43 boxes are necessary.

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