Rian has a factory that manufactures rectangular plant boxes with different sizes - NSC Mathematical Literacy - Question 3 - 2017 - Paper 1
Question 3
Rian has a factory that manufactures rectangular plant boxes with different sizes.
A table showing boxes with different sizes (all external dimensions in mm):
TYPE... show full transcript
Worked Solution & Example Answer:Rian has a factory that manufactures rectangular plant boxes with different sizes - NSC Mathematical Literacy - Question 3 - 2017 - Paper 1
Step 1
3.1.1 Write down the letter (A–E) of the type of plant box that is a cube.
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Answer
The type of plant box that is a cube is box B (dimensions: 325 mm x 325 mm x 225 mm).
Step 2
3.1.2 Calculate the area (in cm²) of the base of box D.
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Answer
To calculate the area of the base of box D:
Convert dimensions from mm to cm:
Length (L) = 1200 mm = 120 cm
Width (W) = 325 mm = 32.5 cm
Area = Length x Width = 120 cm x 32.5 cm = 3900 cm².
Step 3
3.1.3 The area of the base of box A is 1 056,25 cm². Determine the total area (in cm²) needed to store 24 of these boxes if they are stacked on top of each other in a double layer.
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To find the total area needed:
Area of one box (box A) = 1 056,25 cm²
For 24 boxes:
Total area = 24 x 1 056,25 cm² = 25 350 cm².
Since they are stacked in a double layer:
Total area needed = 25 350 cm² / 2 = 12 675 cm².
Step 4
3.1.4 Determine, for box type C, the ratio of the length of the box to the width of the box in simplified form.
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Answer
For box type C:
Length (L) = 600 mm
Width (W) = 325 mm
Ratio of length to width = 600:325 or simplified to 24:13.
Step 5
3.1.5 A municipality bought 148 type E boxes. The inside volume of a type E box is approximately 0,299 m³. They also ordered compost to fill these boxes. The compost is delivered in 6 m³ truckloads.
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Answer
To find the inside volume of the box:
If the inside volume is 9.36% less than the outside volume, we can set:
Inside volume = Outside volume x (1 - 0.0936)
If we denote the outside volume as V, then:
Inside volume = V x 0.9064 = 0,299 m³.
From this we can find:
V = 0,299 m³ / 0.9064 ≈ 0,329 m³.
(b) To find the number of boxes that can be filled with 6 m³ of compost:
Total volume needed for 148 boxes = 148 x 0,299 m³ = 44,252 m³.
Number of boxes filled by 6 m³:
Number of boxes = 6 m³ / 0,299 m³ ≈ 20 boxes.
(c) Minimum number of truckloads:
Total volume of compost = 44,252 m³:
Number of truckloads = Total volume / volume per truckload = 44,252 m³ / 6 m³ ≈ 8 truckloads.