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Gadibola bought Pringles (chips in a cylindrical container) on promotion at a shop - NSC Mathematical Literacy - Question 1 - 2021 - Paper 2

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Gadibola bought Pringles (chips in a cylindrical container) on promotion at a shop. The promotion advertisement is shown below, together with a diagram of the Pringl... show full transcript

Worked Solution & Example Answer:Gadibola bought Pringles (chips in a cylindrical container) on promotion at a shop - NSC Mathematical Literacy - Question 1 - 2021 - Paper 2

Step 1

1.1.1 Determine (in grams) the total mass of the Pringles promotion bought for R100.

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Answer

To find the total mass of Pringles bought for R100, we start by calculating the total number of packs:

Total number of packs=1006=16.6716 packs (since we cannot buy a fraction of a pack)\text{Total number of packs} = \frac{100}{6} = 16.67 \to 16 \text{ packs (since we cannot buy a fraction of a pack)}

Next, the total mass is calculated as follows:

Total mass=16×110 g=1760 g\text{Total mass} = 16 \times 110 \text{ g} = 1760 \text{ g}

Step 2

1.1.2 Write down the radius of a single Pringles container.

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Answer

The radius of the Pringles container is obtained by dividing the diameter by 2:

Radius=64extmm2=32extmm\text{Radius} = \frac{64 ext{ mm}}{2} = 32 ext{ mm}

Step 3

1.1.3 Choose the letter of the answer that will make the following statement TRUE.

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Answer

The correct letter is A. The inner volume of a cylindrical container is measured in cubic meters (m³).

Step 4

1.1.4 Determine the total number of days this promotion is available.

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Answer

To find the total number of days from January 11 to March 31:

  • Days remaining in January: 20 days (January has 31 days, so 31 - 11 = 20)
  • Days in February: 28 days (2021 is not a leap year)
  • Days in March: 31 days

Total days = 20 (Jan) + 28 (Feb) + 31 (Mar) = 79 days.

Step 5

1.1.5 Calculate the price of two 110 g Pringles containers in this promotion.

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Answer

First, we find the price for one Pringles container by dividing the total cost of six:

Price for 1 container=100616.67\text{Price for 1 container} = \frac{100}{6} \approx 16.67

Then, for two containers:

Price for 2 containers=16.67×233.33\text{Price for 2 containers} = 16.67 \times 2 \approx 33.33.

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