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Refer to the figure shown in the question - NSC Mathematical Literacy - Question 3 - 2024 - Paper 2

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Refer to the figure shown in the question. 3.1.1 Calculate the power generated by the wind turbine if the rotor rotates at a speed of 2000 kW. 3.1.2 Discuss the fa... show full transcript

Worked Solution & Example Answer:Refer to the figure shown in the question - NSC Mathematical Literacy - Question 3 - 2024 - Paper 2

Step 1

3.1.1 Calculate the power generated by the wind turbine if the rotor rotates at a speed of 2000 kW.

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Answer

To find the power generated, we confirm the value provided in the question: the power output of the rotor is 2000 kW. Thus, the answer is simply:

Power generated: 2000 kW

Step 2

3.1.2 Discuss the factors that allow rotor blades to produce more energy.

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Answer

Several factors influence the energy production of rotor blades:

  • Blade Design: Improving the aerodynamics of rotor blades can help them capture more wind effectively.

  • Diameter of Rotor: Increasing rotor diameter allows the turbine to sweep more area, capturing more wind and producing more electricity.

  • Wind Speed: Higher wind speeds lead to greater kinetic energy being converted to electrical energy.

  • Technology Advancements: New materials and technologies can enhance structural stability, enabling larger and more efficient turbine designs.

Step 3

3.1.3 Determine the maximum height of the wind turbine in meters, given that the following parameters are provided: Pole height = 124 m Radius = 2 m

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Answer

To calculate the maximum height, we can use the formula:

Max height=Pole height+Radius\text{Max height} = \text{Pole height} + \text{Radius}

Substituting the given values:

Max height=124m+2m=126m\text{Max height} = 124 m + 2 m = 126 m

Maximum height: 126 m

Step 4

3.1.4 Calculate the radius and area of the rotor in square meters.

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Answer

The radius is given as 2 m. To find the area of the rotor, we use the formula for the area of a circle:

A=πr2A = \pi r^2

Substituting the radius value:

A=π(2m)2=π×4m212.57m2A = \pi (2 m)^2 = \pi \times 4 m^2 \approx 12.57 m^2

Thus, the Area of the rotor: approximately 12.57 m²

Step 5

3.1.5 If the increase in energy production is calculated to be 5000 - 800 kW, what is the percentage increase?

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Answer

To find the percentage increase, we can use the formula:

Percentage Increase=New ValueOld ValueOld Value×100\text{Percentage Increase} = \frac{\text{New Value} - \text{Old Value}}{\text{Old Value}} \times 100

Substituting the values:

Percentage Increase=5000800800×100=4200800×100=525%\text{Percentage Increase} = \frac{5000 - 800}{800} \times 100 = \frac{4200}{800} \times 100 = 525\%

Thus, the Percentage Increase: 525%

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