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The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A - NSC Mathematical Literacy - Question 3 - 2016 - Paper 1

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The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A. Study the floor plan and the information given to answer the questions that follow. 1' = 30... show full transcript

Worked Solution & Example Answer:The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A - NSC Mathematical Literacy - Question 3 - 2016 - Paper 1

Step 1

3.1.1 Determine the total number of doors that can be seen on the floor plan.

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Answer

To find the total number of doors visible on the floor plan, count each door symbol shown. Based on the floor plan, there are 21 doors including those that comprise wardrobe doors. Thus, the total number of doors is 21.

Step 2

3.1.2 Give the general direction of the bedroom measuring 11' x 10'4" from the porch.

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Answer

The general direction of the bedroom can be described as North-West, based on its position relative to the porch on the floor plan.

Step 3

3.1.3 Calculate the dimensions of the bedroom measuring 11' x 10'8" in metres.

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Answer

To convert the dimensions from feet to metres:

  • For 11 feet: 11=11imes30.48extcm=335.28extcm=3.3528extm11' = 11 imes 30.48 ext{ cm} = 335.28 ext{ cm} = 3.3528 ext{ m}

  • For 10'8": 108"=10.67imes30.48extcm=326.46extcm=3.2646extm10'8" = 10.67 imes 30.48 ext{ cm} = 326.46 ext{ cm} = 3.2646 ext{ m}

Thus, the dimensions of the bedroom in metres are approximately 3.35 m x 3.26 m.

Step 4

3.1.4 Determine the scale used in the form of 1 : ...

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Answer

From the problem statement, the scale is given as 1.5 cm representing 3.375 m on the building. To determine the scale:

  • We express this in the form of 1 : X where X is the number of metres represented by 1 cm on the scale.

1.5extcm:3.375extm=1:(3.375/1.5)extm=1:2.251.5 ext{ cm} : 3.375 ext{ m} = 1 : (3.375/1.5) ext{ m} = 1 : 2.25

Thus, the scale of the floor plan is 1 : 225.

Step 5

3.2.1 Mr Dan departed from East London. Write down the departure time from East London and arrival time.

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Answer

Mr. Dan departed from East London at 09:00 on Friday, arriving in Johannesburg at 11:15 on Saturday.

Step 6

3.2.2 Identify the station where Shosholoza-Meyl train stopped for the longest duration.

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Answer

The station where the Shosholoza-Meyl train stopped for the longest duration is Burgersdorp.

Step 7

3.2.3 Calculate the average speed of the journey (East London–Johannesburg).

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Answer

Calculating total time:

  • Total journey time = 24:00 - 09:00 = 3 hours and 33 minutes = 3.55 hours

  • To find the distance, we use: extDistance=992extkm ext{Distance} = 992 ext{ km}

Using the formula for average speed:

ext{Average speed} = rac{ ext{Distance}}{ ext{Time}} = rac{992 ext{ km}}{3.55 ext{ hours}} = 60.30 ext{ km/h}

Thus, the average speed of the journey is approximately 60.30 km/h.

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