The graphs below show the water tariffs for Cape Town and Johannesburg - NSC Mathematical Literacy - Question 1 - 2018 - Paper 1
Question 1
The graphs below show the water tariffs for Cape Town and Johannesburg. Study the graphs below and answer the questions which follow.
CAPE TOWN
Kilolitres (kℓ) used... show full transcript
Worked Solution & Example Answer:The graphs below show the water tariffs for Cape Town and Johannesburg - NSC Mathematical Literacy - Question 1 - 2018 - Paper 1
Step 1
State the type of graph used to represent this data.
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Answer
The graph used to represent this data is a horizontal bar graph, also known as a double or compound bar graph.
Step 2
Arrange Cape Town's percentage increase in descending order.
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Answer
The percentage increases for Cape Town are arranged in descending order as follows:
71,6%
51%
10,3%
10,2%
7,3%
6,6%
Step 3
Identify the step that indicates the largest increase (in rand) in Cape Town's water tariff from 2016/17 to 2017/18.
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Step 6 indicates the largest increase in Cape Town's water tariff, going from R66,41 to R200,10.
Step 4
Determine in which ONE of the two cities water is more expensive.
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Answer
Cape Town has a higher price for water usage than Johannesburg. The maximum price in Cape Town for using over 50 kl is R302,24, while Johannesburg caps at R38,72 for the same usage.
Step 5
Calculate the cost of 3,5 kℓ of water in Johannesburg during 2017/18.
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The cost for 3,5 kℓ in Johannesburg is R7,14, as it falls within the 0-6 kl range which is free.
Step 6
Is the data given categorically or numerically?
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The data is given numerically, as it involves numerical measurements of water usage and cost.
Step 7
Explain the term cost price.
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The cost price refers to the amount of money spent to produce a product, including all expenses like materials, labor, and overhead before any profit margin is added.
Step 8
Calculate the cost price of CLOCK A, excluding VAT.
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Answer
To calculate the cost price of CLOCK A, we must subtract the profit from the selling price. Therefore:
Cost Price = Selling Price - Profit = R350,00 - R914,00 = R2 436,00.
Step 9
Write down the time on CLOCK B, using the 24-hour format if it represents the time in the evening.
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The time on CLOCK B in 24-hour format is 20:00.
Step 10
Calculate the total profit made if all four clocks are sold.
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Total profit = Profit of CLOCK A + Profit of CLOCK B + Profit of CLOCK C + Profit of CLOCK D\Total Profit = R914,00 + R60,00 + R573,00 + R1 623,00 = R3 170,00.
Step 11
Convert the total mass of the fruit into kg.
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To convert the total mass of the fruit into kilograms, we divide the total grams by 1,000:
Total weight = 394 g / 1,000 = 0.394 kg.
Step 12
The pear is removed from the kitchen scale. Write down the new reading (in grams) shown on the kitchen scale.
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The new reading on the kitchen scale after removing the pear is 266 g.
Step 13
Show how the mass of 202 g for the peach was calculated.
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To find the mass of the peach, we calculate:
Mass of Plum = 128 g / 2 = 64 g.
The mass of the peach is then the remaining weight:
Mass of Peach = Total Mass - Mass of Pear - Mass of Plum
= 394 g - 128 g - 64 g = 202 g.
Step 14
Determine the probability of randomly selecting a banana from the fruit placed on the kitchen scale.
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To determine this probability, note that there are three fruits in total, but no banana is mentioned. Therefore, the probability of selecting a banana is 0.
Step 15
Write down the simplified ratio of the total mass of fruit to the total mass on the scale.
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The total mass of the fruit is 394 g and the total mass on the scale is also 394 g. Therefore, the simplified ratio is 1:1.
