Use TABLE 2 above to answer the questions that follow - NSC Mathematical Literacy - Question 3 - 2022 - Paper 1
Question 3
Use TABLE 2 above to answer the questions that follow.
3.1.1 Write down the province with the second highest number of sheep for February 2021.
3.1.2 Calculate Eas... show full transcript
Worked Solution & Example Answer:Use TABLE 2 above to answer the questions that follow - NSC Mathematical Literacy - Question 3 - 2022 - Paper 1
Step 1
Write down the province with the second highest number of sheep for February 2021.
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Answer
To find the province with the second highest number of sheep for February 2021, we refer to the table:
Western Cape: 2497
Northern Cape: 1434
Free State: 2415
Eastern Cape: 1961
KwaZulu-Natal: 668
Mpumalanga: 78
Limpopo: 503
Gauteng: 94
North West: 651
The province with the highest number is the Western Cape, followed by the Free State with 2415 sheep.
Thus, the answer is Free State.
Step 2
Calculate Eastern Cape's estimated total number of livestock for August 2020.
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Answer
The table shows the following livestock numbers for Eastern Cape in August 2020:
Cattle: 3,050
Sheep: 3,059
Goats: 1,631
To calculate the total: extTotal=extCattle+extSheep+extGoats
Substituting in the values: extTotal=3050+3059+1631=7740
Therefore, Eastern Cape's estimated total number of livestock for August 2020 is 7740.
Step 3
The provincial mean number of sheep is 400 444.
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Answer
To verify the farmer's statement about the missing value A, we will first determine the total number of sheep from the given data:
Total sheep as per the table: extTotalSheep=2497+1434+2415+1961+668+78+503+94+651
Calculating each step:
Western Cape: 2497
Northern Cape: 1434
Free State: 2415
Eastern Cape: 1961
KwaZulu-Natal: 668
Mpumalanga: 78
Limpopo: 503
Gauteng: 94
North West: 651
Summing these values: extTotal=2497+1434+2415+1961+668+78+503+94+651=10,447
The mean number of sheep is given by: ext{Mean} = rac{ ext{Total}}{N} where N is the number of provinces (9).
Calculating the mean: ext{Mean} = rac{10447}{9} ext{ which gives } 1160.78
Since the mean is 400,444, we deduce: A<200 is not valid because we need to use calculated means for realistic comparisons.