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The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A - NSC Mathematical Literacy - Question 3 - 2016 - Paper 1

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The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A. Study the floor plan and the information given to answer the questions that follow. 1' = 3... show full transcript

Worked Solution & Example Answer:The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A - NSC Mathematical Literacy - Question 3 - 2016 - Paper 1

Step 1

3.1.1 Determine the total number of doors that can be seen on the floor plan.

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Answer

To find the total number of doors depicted in the floor plan, count all visible doors. Exclude any wardrobe doors if mentioned. The accurate count observed is 21 doors.

Step 2

3.1.2 Give the general direction of the bedroom measuring 11' × 10'4" from the porch.

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Answer

The bedroom's general direction from the porch is North West.

Step 3

3.1.3 Calculate the dimensions of the bedroom measuring 11' × 10'8" in metres.

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Answer

To convert the dimensions from feet to metres:

1 foot = 0.3048 m.

  1. For the length:

    11=11imes0.3048=3.3528extm11' = 11 imes 0.3048 = 3.3528 ext{ m}

  2. For the width:

    = 10.6667 imes 0.3048 = 3.2512 ext{ m} $$

Thus, the dimensions of the bedroom in metres are approximately 3.3528 m by 3.2512 m.

Step 4

3.1.4 The floor plan was drawn using a scale of 1,5 cm on the floor plan to represent 3,375 m on the actual building. Determine the scale used in the form of 1 : ...

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Answer

To find the scale, use the relationship that:

1.5 cm on the floor plan represents 3,375 m in reality.

To express this in the required form:

  • Convert 1.5 cm to meters:

    1.5 ext{ cm} = rac{1.5}{100} ext{ m} = 0.015 ext{ m}

  • Then set up the ratio:

    0.015:33750.015 : 3375

Now divide both sides by 0.015:

1 : rac{3375}{0.015} = 1 : 225000

Hence, the scale is 1 : 225000.

Step 5

3.2.1 Mr Dan departed on Friday from East London to meet an agent in Johannesburg on Saturday at 11:15 am as per arrangement. Write down the departure time from East London and arrival time in Johannesburg.

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Answer

Mr. Dan departed from East London at 09:00 am on Friday.

Step 6

3.2.2 Identify the station where Shosholoza-Meyl train stopped for the longest duration.

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Answer

The Shosholoza-Meyl train stopped for the longest duration at Burgersdorp.

Step 7

3.2.3 The total time spent at the stations during the journey was 3 hours and 33 minutes. Calculate the average speed of the journey (East London–Johannesburg). Give your answer in Km/h.

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Answer

First, calculate the total travel time. If we assume:

  • Departure time: 09:00 am
  • Arrival time: 16:27 pm (based on 24-hour time conversion)

Total travel time:

(16:2709:00)=7exthoursand27extminutes(16:27 - 09:00) = 7 ext{ hours and } 27 ext{ minutes}

Convert 27 minutes into hours:

27 ext{ min} = rac{27}{60} = 0.45 ext{ hours}

Therefore, total travel time in hours = 7 + 0.45 = 7.45 hours.

Given total distance as 992 km:

  • Average speed = total distance / total time:

ext{Average speed} = rac{992 ext{ km}}{7.45 ext{ hours}} ext{, approximately } 133.16 ext{ Km/h}

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