4.1.1 Median 4.1.2 Upper quartile The school-based assessment (SBA) marks and percentages of the ten lowest performing learners in Mathematical Literacy of a particular school in 2016 are represented in TABLE 5 below - NSC Mathematical Literacy - Question 4 - 2017 - Paper 1

To find the modal actual SBA percentage mark, we first list the percentage marks for each learner:

• A: 46%
• B: 48%
• C: 34%
• D: 29%
• E: 31%
• F: 36%
• G: 41%
• H: 39%
• I: 39%
• J: 39%

The marks with the highest frequency are 39%, which appears 3 times. Thus, the modal actual SBA percentage mark is 39%.

From the previously listed SBA percentage marks, Learner D has the lowest actual SBA percentage mark of 29%.

To calculate the mean SBA percentage mark, we sum all the individual percentage marks and divide by the number of learners:

• Total SBA percentage marks = 46 + 48 + 34 + 29 + 31 + 36 + 41 + 39 + 39 + 39 = 413
• Number of learners = 10

Now, calculating the mean:

ext{Mean} = rac{413}{10} = 41.3

Learner J qualifies for an adjusted SBA percentage mark due to a valid medical certificate. To adjust Learner J's mark, we reconsider their actual SBA percentage mark in context with the other learners. Assuming Learner J's missed task is averaged into the total available marks:

Adjusted Mark = 137 + Additional Points (due to missed task calculation based on institutional guidelines)

Without specific adjustments stated, we assume the adjusted mark may affect their performance. For the probability of Learner J achieving a better average, we consider their prior performance reflected in the averages, raising it from 39%.

The estimated 2015 midyear total population is represented by option A: Fifty-four million, nine hundred and fifty-seven thousand, seven hundred and sixty-four.

Upon examining TABLE 6, we can identify that the age group 15-19 for the Indians/Asians has the same number of males and females, both being 431,779.

To calculate the missing value Y, we sum the counts of males and females from the provided age groups:

$Y = 426 516 + 430 667 + 431 779 + 437 412 + 1 558 886 + 1 155 775 + 365 544 + 31 698$

Calculating this yields: $Y = 4 832 917.$

Using the given data for the total population of South Africa which is 54 957 764, we can find the probability:

Total coloured males = 2 334 819

ext{Probability} = rac{2 334 819}{54 957 764} imes 100 ext{%} \\ = 4.25\%

Using the population estimates:

• Asian females = 674 730
• Asian males = 688 118

The ratio is: ext{Ratio} = rac{674 730}{688 118} = rac{337 365}{344 059}

This simplifies to approximately 0.98:1.

The number of coloured females is given as 2 498 098.

The total population is 54 957 764.

Calculating the percentage:

ext{Percentage} = rac{2 498 098}{54 957 764} imes 100 \\ ext{Percentage} ext{ of coloured females} = 4.54\%

Examining TABLE 6, the age group 0-4 has the largest number of people, totaling 426,516 males and 425,250 females.

The best graphical representation for the data in TABLE 6 is a bar graph, as it effectively shows comparative data across different categories.