Photo AI

Keitumetse is a South African student who is on holiday in Australia - NSC Mathematical Literacy - Question 4 - 2020 - Paper 2

Question icon

Question 4

Keitumetse-is-a-South-African-student-who-is-on-holiday-in-Australia-NSC Mathematical Literacy-Question 4-2020-Paper 2.png

Keitumetse is a South African student who is on holiday in Australia. He went to the Lawrence Theatre to attend a musical concert. ANNEXURE D shows the seating arra... show full transcript

Worked Solution & Example Answer:Keitumetse is a South African student who is on holiday in Australia - NSC Mathematical Literacy - Question 4 - 2020 - Paper 2

Step 1

4.1.1 Determine, as a percentage, the probability of randomly selecting an odd numbered seat for a disabled person from all the seats in the theatre.

96%

114 rated

Answer

To determine the probability of selecting an odd numbered seat, we first need to find the total number of seats in the theatre. Assuming there are 'N' seats, the odd numbered seats would thus be 'N/2' (since half of them would be odd).

The probability (P) can be computed using the formula:

P=Number of odd seatsTotal seats×100%P = \frac{\text{Number of odd seats}}{\text{Total seats}} \times 100\, \%

Substituting values, we write that probability as:

P=N/2N×100%=50%P = \frac{N/2}{N} \times 100\, \% = 50\, \%

Step 2

4.1.2 Identify the row and seat number for a person who is seated as follows: • In Section B • Fourth row from the stage • In the middle seat

99%

104 rated

Answer

In Section B, if we consider the seating arrangement provided,

  • The rows typically are numbered from the stage back. Thus, the fourth row from the stage would be Row 4.
  • For the middle seat in the row, if there are, for example, 12 seats in Section B, the middle seat would be Seat 6 or 7, depending on how you define 'middle.' Therefore, the seat number would be either 6 or 7, assuming average conditions.

Step 3

4.1.3 Keitumetse is seated in D7 of Section A. He has to assist his friend in A11 after the show. Describe the shortest possible path he would follow to reach A11.

96%

101 rated

Answer

To reach A11 from D7:

  1. From D7, Keitumetse should walk to the nearest aisle in Section A.
  2. Then, he will move towards the front of the section until reaching Row A.
  3. Once he reaches Row A, he will turn left and walk to seat 11.

This path will ensure he takes the shortest route across the seating arrangement.

Step 4

4.1.4 Sections A to C had the following number of people attending on a Thursday. ADULTS STUDENT CHILDREN (14 AND YOUNGER) Section A 53 15 9 Section B 57 32 15 Section C 40 10 8 Verify, with calculations, whether this claim is CORRECT.

98%

120 rated

Answer

First, we compute the total attendance from the table given:

  • Adults: 53 + 57 + 40 = 150
  • Students: 15 + 32 + 10 = 57
  • Children: 9 + 15 + 8 = 32

The total attendance is: extTotal=150+57+32=239 ext{Total} = 150 + 57 + 32 = 239

To verify the claim of $5,796 excluding VAT, we first need to ensure we understand ticket prices.

Assuming adults 34.70,students34.70, students 30.50, and children $17.60, the total ticket income can be calculated as:

Income=(150×34.70)+(57×30.50)+(32×17.60)\text{Income} = (150 \times 34.70) + (57 \times 30.50) + (32 \times 17.60)

Which gives: Income=5205+1738.5+563.2=7506.7AUD\text{Income} = 5205 + 1738.5 + 563.2 = 7506.7\, \text{AUD}

Factoring in a VAT of 10%, it is calculated as: Net Income=7506.71.1=6815.18AUD\text{Net Income} = \frac{7506.7}{1.1} = 6815.18\, \text{AUD}

This claim is incorrect as it exceeds $5,796.

Step 5

4.1.5 Keitumetse bought a ticket for a Friday show. Calculate how much the ticket costs in South African rand.

97%

117 rated

Answer

For a Friday ticket, he pays $34.70.

Converting AUD to ZAR using the provided exchange rate:

Cost in ZAR=34.70AUD×14.43ZAR/AUD\text{Cost in ZAR} = 34.70\, \text{AUD} \times 14.43\, \text{ZAR/AUD}

This gives: Cost in ZAR500.64ZAR\text{Cost in ZAR} \approx 500.64\, \text{ZAR}

Join the NSC students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;