The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A - NSC Mathematical Literacy - Question 3 - 2016 - Paper 1
Question 3
The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A. Study the floor plan and the information given to answer the questions that follow.
1' = 30... show full transcript
Worked Solution & Example Answer:The floor plan of a house on sale in Johannesburg is shown on ANNEXURE A - NSC Mathematical Literacy - Question 3 - 2016 - Paper 1
Step 1
Determine the total number of doors that can be seen on the floor plan.
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Answer
The total number of doors visible on the floor plan is 18, excluding wardrobe doors.
Step 2
Give the general direction of the bedroom measuring 11' x 10'4" from the porch.
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Answer
The general direction of the bedroom from the porch is North West.
Step 3
Calculate the dimensions of the bedroom measuring 11' x 10'8" in metres.
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Answer
To convert the dimensions from feet to metres:
1' = 0.3048 m. Thus, for the dimensions:
Width: 11' = 11 \times 0.3048 = 3.3528,m,
Height: 10'8" = (10 + \frac{8}{12})' \times 0.3048 = 3.2512,m.
The dimensions are approximately 3.3528 m by 3.2512 m.
Step 4
The floor plan was drawn using a scale of 1.5 cm on the floor plan to represent 3,375 m on the actual building. Determine the scale used in the form of 1 : ...
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Answer
Given the scale of 1.5 cm for 3.375 m, we can calculate the scale. Setting up the ratio,
\frac{1.5 cm}{3.375 m} = \frac{1}{x},
we find x = 225. Therefore, the scale is 1 : 225.
Step 5
Mr Dan departed on Friday from East London to meet an agent in Johannesburg on Saturday at 11:15 am as per arrangement. Write down the departure time from East London and arrival time in Johannesburg.
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Answer
Mr. Dan departed from East London at 09:00 on Friday.
Step 6
Identify the station where Shosholoza-Meyl train stopped for the longest duration.
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Answer
The station where the Shosholoza-Meyl train stopped for the longest duration is Burgersdorp.
Step 7
The total time spent at the stations during the journey was 3 hours and 33 minutes. Calculate the average speed of the journey (East London–Johannesburg). Give your answer in Km/h.
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Answer
To find the average speed, we first convert the total time: 3 hours and 33 minutes = 3 + \frac{33}{60} = 3.55 hours.
The distance from East London to Johannesburg is 992 km. Using the formula for average speed:
Average speed = \frac{distance}{time} = \frac{992 km}{(24:00 - 09:00) - 3.55} = 60.30 \text{ km/h}.
