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8.1 Write down, with a reason, the size of $ar{S}$ - NSC Mathematics - Question 8 - 2017 - Paper 2

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8.1 Write down, with a reason, the size of $ar{S}$. 8.1.2 If the diameter is 20 cm and SP = 16 cm, calculate the length of TU. 8.2 ABC is a tangent to circle BQPR... show full transcript

Worked Solution & Example Answer:8.1 Write down, with a reason, the size of $ar{S}$ - NSC Mathematics - Question 8 - 2017 - Paper 2

Step 1

Write down, with a reason, the size of $ar{S}$

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Answer

Sˉ=90 (Angle in a semi-circle is a right angle)\bar{S} = 90^{\circ} \text{ (Angle in a semi-circle is a right angle)}

Step 2

If the diameter is 20 cm and SP = 16 cm, calculate the length of TU.

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Answer

Given the diameter PR=20PR = 20 cm, the radius QP=10QP = 10 cm. Using the Pythagorean Theorem:

QT2=QP2SP2QT^2 = QP^2 - SP^2

Substituting the values:

QT2=10282=10064=36QT^2 = 10^2 - 8^2 = 100 - 64 = 36

Therefore, QT=6QT = 6 cm. The length of TU=QUQT=106=4TU = QU - QT = 10 - 6 = 4 cm.

Step 3

Calculate, with reasons, the size of $ar{B_1}$

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Answer

B1ˉ=30 (Tangent-chord theorem)\bar{B_1} = 30^{\circ} \text{ (Tangent-chord theorem)}

Step 4

Calculate, with reasons, the size of $ar{P_2}$

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Answer

P2ˉ=75 (Angles in the same segment are equal)\bar{P_2} = 75^{\circ} \text{ (Angles in the same segment are equal)}

Step 5

Calculate, with reasons, the size of $ar{R}$

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Answer

Rˉ=1803070=80 (Sum of angles in a triangle)\bar{R} = 180^{\circ} - 30^{\circ} - 70^{\circ} = 80^{\circ} \text{ (Sum of angles in a triangle)}

Step 6

Calculate, with reasons, the size of $ar{Q_2}$

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Answer

Q2ˉ=15 (Opposite angles in cyclic quadrilateral)\bar{Q_2} = 15^{\circ} \text{ (Opposite angles in cyclic quadrilateral)}

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