In the diagram, W is a point on the circle with centre O - NSC Mathematics - Question 10 - 2017 - Paper 2
Question 10
In the diagram, W is a point on the circle with centre O. V is a point on OW. Chord MN is drawn such that MV = VN. The tangent at W meets OM produced at T and ON pro... show full transcript
Worked Solution & Example Answer:In the diagram, W is a point on the circle with centre O - NSC Mathematics - Question 10 - 2017 - Paper 2
Step 1
10.1 Give a reason why OV ⊥ MN.
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Answer
The line from the centre O to the midpoint of the chord MN is perpendicular to the chord itself. Therefore, since V lies on this line, we have OV ⊥ MN.
Step 2
10.2.1 MN || TS
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Answer
To prove that MN || TS, we observe that the angles subtended by the same arc are equal. Therefore, we can establish that:
∠OWT=∠OMV
Since these angles are equal, by the corresponding angles criterion, we conclude that MN || TS.
Step 3
10.2.2 TMNS is a cyclic quadrilateral
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Answer
To prove that TMNS is a cyclic quadrilateral, we need to show that the opposite angles are supplementary. We can ascertain:
∠MTS+∠MNS=180∘
This is derived from the fact that angles subtended by the same chord are equal, which fulfills the requirement for TMNS being a cyclic quadrilateral.
Step 4
10.2.3 OS ⋅ MN = 2ON ⋅ WS
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Answer
To prove the relationship between OS, MN, ON, and WS:
We first establish that OV = VN, as given in the problem statement.
Then, since we have the angles in triangles AOV and AOW equal, we can use similarity:
ONOS=VNWS.
Applying the property of similar triangles, we can multiply both sides by ON and substitute to derive the equation: OS⋅MN=2ON⋅WS.