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In the diagram, points A, B, D and C lie on a circle - NSC Mathematics - Question 8 - 2017 - Paper 2

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In the diagram, points A, B, D and C lie on a circle. CE || AB with E on AD produced. Chords CB and AD intersect at F. \( D_1 = 50° \) and \( C_1 = 15° \). 8.1 Calc... show full transcript

Worked Solution & Example Answer:In the diagram, points A, B, D and C lie on a circle - NSC Mathematics - Question 8 - 2017 - Paper 2

Step 1

8.1.1 Calculate, with reasons, the size of: \( \hat{A} \)

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Answer

Given ( E = 50° - 15° = 35° ) (by the exterior angle of triangle AFB) and ( \hat{A} + \hat{E} = 180° ) since they are co-interior angles with ( CE || AB ).

Thus, ( \hat{A} = 180° - (130° + 15°) = 35° ) (by alternate angles, given ( CE || AB )). Therefore, ( \hat{A} = 35° ).

Step 2

8.1.2 Calculate, with reasons, the size of: \( C_2 \)

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Answer

Since ( C_2 = \hat{E} ) (as angles in the same segment), we find that ( C_2 = 35° ) because ( \hat{E} = 35° ) as calculated above.

Step 3

8.2 Prove, with a reason, that CF is a tangent to the circle passing through points C, D and E.

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Answer

To prove that CF is a tangent to the circle at point C, we observe that the angle between CF and the chord CD is equal to angle C1 (the angle in the alternate segment). Hence, since ( C_1 = 15° ) and ( C_2 = 35° ) are equal (angles in the same segment), we conclude that CF is tangent to the circle at point C (by the converse of the tangent-chord theorem).

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