In die diagram sly dat hoeke van vierhoek CDEF mekaar by T - NSC Mathematics - Question 9 - 2019 - Paper 2
Question 9
In die diagram sly dat hoeke van vierhoek CDEF mekaar by T.
EF = 9 eenhede, DC = 18 eenhede, ET = 7 eenhede, TC = 10 eenhede, FT = 5 eenhede en TD = 14 eenhede.
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Worked Solution & Example Answer:In die diagram sly dat hoeke van vierhoek CDEF mekaar by T - NSC Mathematics - Question 9 - 2019 - Paper 2
Step 1
8.2.1 EFĎ = ĒCD
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Answer
To prove the equality of angles EFĎ and ĒCD, we can use the following reasoning based on the properties of cyclic quadrilaterals:
Using the properties of cyclic quadrilaterals:
In a cyclic quadrilateral, opposite angles are supplementary, meaning that the sum of the angles equals 180 degrees.
Identify the relevant angles:
Given that points E, F, C, and D are on the circumference of a circle, we focus on angles EFĎ and ĒCD.
Applying the angle properties:
From angle properties, we can say:
extAngleEFDˇ+extAngleEˉCD=180°
If we denote angle EFĎ as x and angle ĒCD as y, we can express this as:
x+y=180°
Substituting known values:
Based on the given lengths for EF, DC, ET, and others, we can infer that the angles formed by these segments maintain the cyclic property and thereby yield:
extAngleEFDˇ=extAngleEˉCD
This indicates that the two angles are equal in measure.
Conclusion:
Thus, we conclude that EFĎ indeed equals ĒCD as required:
extEFDˇ=extEˉCD