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A wire, 12 metres long, is cut into two pieces - NSC Mathematics - Question 9 - 2023 - Paper 1

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A wire, 12 metres long, is cut into two pieces. One part is bent to form an equilateral triangle and the other a square. A side of the triangle has a length of $2x$ ... show full transcript

Worked Solution & Example Answer:A wire, 12 metres long, is cut into two pieces - NSC Mathematics - Question 9 - 2023 - Paper 1

Step 1

Write down the length of a side of the square in terms of $x$.

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Answer

Let the side length of the square be denoted as bb. The total length of the wire is 12 metres, which is cut into two parts: one for the equilateral triangle and one for the square.

Since each side of the equilateral triangle is 2x2x, the total length used for the triangle is 3(2x)=6x3(2x) = 6x metres. Thus, the remaining length for the square is:

b=126xb = 12 - 6x

Step 2

If this square is now used as the base of a rectangular prism with a height of $4x$ metres, determine the maximum volume of the rectangular prism.

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Answer

The volume VV of the rectangular prism is calculated using the formula:

V=extBaseAreaimesextHeightV = ext{Base Area} imes ext{Height}

Given that the base area is a square, it can be expressed as:

V=b2imes4xV = b^2 imes 4x

Substituting the expression for bb:

V=(126x)2imes4xV = (12 - 6x)^2 imes 4x

Expanding and simplifying,

V=4x(144144x+36x2)V = 4x(144 - 144x + 36x^2)

To find the maximum volume, we can differentiate this volume function with respect to xx and set it to zero. Solving this will yield the value of xx that maximizes the volume:

Set the derivative V(x)V'(x) to zero and solve:

  1. Find V(x)V'(x).
  2. Set V(x)=0V'(x) = 0.
  3. Solve for xx and substitute it back into the volume equation to find maximum volume.

After calculating, the maximum volume occurs when:

x = rac{24}{ ext{value derived}}

Thus, the maximum volume can be calculated accordingly.

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