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Sketched below is the graph of $f(x) = k^x; k > 0$ - NSC Mathematics - Question 6 - 2019 - Paper 1

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Sketched below is the graph of $f(x) = k^x; k > 0$. The point $(4; 16)$ lies on $f$. 5.1 Determine the value of $k$. 5.2 Graph $g$ is obtained by reflecting graph ... show full transcript

Worked Solution & Example Answer:Sketched below is the graph of $f(x) = k^x; k > 0$ - NSC Mathematics - Question 6 - 2019 - Paper 1

Step 1

Determine the value of $k$

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Answer

To find the value of kk, we use the point (4;16)(4; 16) which lies on the graph of f(x)=kxf(x) = k^x.

Substituting the coordinates into the function: f(4)=k4=16.f(4) = k^4 = 16.
Taking the fourth root of both sides gives: k=161/4=2.k = 16^{1/4} = 2.
Thus, the value of kk is 2.

Step 2

Determine the equation of graph $g$

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Answer

Reflecting the graph ff about the line y=xy = x helps us find the equation of graph gg. The transformation related to the reflection implies that if y=kxy = k^x, then for graph gg, we express xx in terms of yy.

Starting from: y=kx extbecomesx=ky.y = k^x \ ext{ becomes } x = k^y.
Substituting k=2k = 2 gives: x=2y.x = 2^y.
In standard function form, the equation for graph gg is: y = rac{ ext{log}_2(x)}{}.

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