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'n Maatskappy gebruik 'n koderingstelsel om sy kliente te identifiseer - NSC Mathematics - Question 11 - 2017 - Paper 1

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'n Maatskappy gebruik 'n koderingstelsel om sy kliente te identifiseer. Elke kode bestaan uit twee letters en 'n ry syfers, byvoorbeeld AD108 of RR 45789. Die lette... show full transcript

Worked Solution & Example Answer:'n Maatskappy gebruik 'n koderingstelsel om sy kliente te identifiseer - NSC Mathematics - Question 11 - 2017 - Paper 1

Step 1

Hoeveel verskillende kliente kan geidentifiseer word met 'n koderingstelsel wat uit TWEE letters en TWEE syfers bestaan?

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Answer

To determine the total number of unique client codes, we can use the formula for combinations:

  1. Selecting Letters:

    • There are 5 letters (A, D, R, S, U) available.
    • The number of ways to choose 2 letters with repetition allowed is: 5imes5=255 imes 5 = 25
  2. Selecting Digits:

    • The digits range from 0 to 9 (10 options).
    • The number of ways to choose 2 digits without repetition is: 10imes9=9010 imes 9 = 90
  3. Total Combinations:

    • Therefore, the total number of unique client identifiers is: extTotal=25imes90=2250 ext{Total} = 25 imes 90 = 2250

Step 2

Bepaal die kleinste getal syfers wat 'n maatskappy nodig het om 700 000 kliente op unieke wyse met hul kodeeringstelsel te identifiseer.

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Answer

To find the smallest number of digits required to uniquely identify 700,000 clients, we can calculate as follows:

  1. Using 0 digits:

    • With 2 letters: 5imes5=255 imes 5 = 25
    • Total: 25imes1=2525 imes 1 = 25
  2. Using 1 digit:

    • Total: 5imes10=505 imes 10 = 50
  3. Using 2 digits:

    • Total: 5imes10imes9=4505 imes 10 imes 9 = 450
  4. Using 3 digits:

    • Total: 5imes10imes9imes8=36005 imes 10 imes 9 imes 8 = 3600
  5. Using 4 digits:

    • Total: 5imes10imes9imes8imes7=252005 imes 10 imes 9 imes 8 imes 7 = 25200
  6. Using 5 digits:

    • Total: 5imes10imes9imes8imes7imes6=1512005 imes 10 imes 9 imes 8 imes 7 imes 6 = 151200

Summarizing these values:

  • After checking combinations with increasing digits, we find that:
    • For 6 digits, we have: 5imes10imes9imes8imes7imes6=7560005 imes 10 imes 9 imes 8 imes 7 imes 6 = 756000
    • This value exceeds 700,000, thus allowing for unique identification.

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