'n Maatskappy gebruik 'n koderingstelsel om sy kliente te identifiseer - NSC Mathematics - Question 11 - 2017 - Paper 1
Question 11
'n Maatskappy gebruik 'n koderingstelsel om sy kliente te identifiseer. Elke kode bestaan uit twee letters en 'n ry syfers, byvoorbeeld AD108 of RR 45789.
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Worked Solution & Example Answer:'n Maatskappy gebruik 'n koderingstelsel om sy kliente te identifiseer - NSC Mathematics - Question 11 - 2017 - Paper 1
Step 1
Hoeveel verskillende kliente kan geidentifiseer word met 'n koderingstelsel wat uit TWEE letters en TWEE syfers bestaan?
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Answer
To determine the total number of unique client codes, we can use the formula for combinations:
Selecting Letters:
There are 5 letters (A, D, R, S, U) available.
The number of ways to choose 2 letters with repetition allowed is:
5imes5=25
Selecting Digits:
The digits range from 0 to 9 (10 options).
The number of ways to choose 2 digits without repetition is:
10imes9=90
Total Combinations:
Therefore, the total number of unique client identifiers is:
extTotal=25imes90=2250
Step 2
Bepaal die kleinste getal syfers wat 'n maatskappy nodig het om 700 000 kliente op unieke wyse met hul kodeeringstelsel te identifiseer.
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Answer
To find the smallest number of digits required to uniquely identify 700,000 clients, we can calculate as follows:
Using 0 digits:
With 2 letters: 5imes5=25
Total: 25imes1=25
Using 1 digit:
Total: 5imes10=50
Using 2 digits:
Total: 5imes10imes9=450
Using 3 digits:
Total: 5imes10imes9imes8=3600
Using 4 digits:
Total: 5imes10imes9imes8imes7=25200
Using 5 digits:
Total: 5imes10imes9imes8imes7imes6=151200
Summarizing these values:
After checking combinations with increasing digits, we find that:
For 6 digits, we have:
5imes10imes9imes8imes7imes6=756000
This value exceeds 700,000, thus allowing for unique identification.