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The functions $f(x) = -x^2 - 2x + 3$ and $g(x) = mx + c$ are drawn below, with $g$ passing through $E$, $C$ and $A$ - NSC Mathematics - Question 4 - 2016 - Paper 1

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The-functions-$f(x)-=--x^2---2x-+-3$-and-$g(x)-=-mx-+-c$-are-drawn-below,-with-$g$-passing-through-$E$,-$C$-and-$A$-NSC Mathematics-Question 4-2016-Paper 1.png

The functions $f(x) = -x^2 - 2x + 3$ and $g(x) = mx + c$ are drawn below, with $g$ passing through $E$, $C$ and $A$. A and B are the x-intercepts of $f$, and $CD$ is... show full transcript

Worked Solution & Example Answer:The functions $f(x) = -x^2 - 2x + 3$ and $g(x) = mx + c$ are drawn below, with $g$ passing through $E$, $C$ and $A$ - NSC Mathematics - Question 4 - 2016 - Paper 1

Step 1

Determine the coordinates of C, the turning point of the graph of f.

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Answer

To find the turning point of the quadratic function f(x)=x22x+3f(x) = -x^2 - 2x + 3, we first need to use the vertex formula. The x-coordinate of the vertex (turning point) can be found using: x=b2ax = -\frac{b}{2a} where a=1a = -1 and b=2b = -2. Thus: x=22(1)=1x = -\frac{-2}{2(-1)} = 1 Next, substitute x=1x = 1 back into the function to find the y-coordinate: f(1)=122(1)+3=0f(1) = -1^2 - 2(1) + 3 = 0 Therefore, the coordinates of C are (1,0)(1, 0).

Step 2

Determine the coordinates of A and B.

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Answer

To find the x-intercepts (points A and B) of the graph f(x)f(x), set f(x)=0f(x) = 0: x22x+3=0-x^2 - 2x + 3 = 0 Multiplying through by -1, we get: x2+2x3=0x^2 + 2x - 3 = 0 Factoring the quadratic: (x+3)(x1)=0(x + 3)(x - 1) = 0 Thus, the solutions are: x=3extandx=1x = -3 ext{ and } x = 1 This means the coordinates of A and B are A(3,0)A(-3, 0) and B(1,0)B(1, 0). However, since point C is on the graph as well, only A has a distinct x-coordinate.

Step 3

Determine the values of m and c.

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Answer

Since line g(x)=mx+cg(x) = mx + c passes through point C (1, 0) and point E (at the y-intercept of g), we can write two equations. The line passes through C, hence: 0=m(1)+c0 = m(1) + c Thus: c=mc = -m Using the coordinates of another point known, we would need to know the coordinates of E to solve for m and c. If not known, we shall retain the equation c=mc = -m.

Step 4

Calculate the length of CE. (leave your answer in surd form)

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Answer

To find length CECE, we would use the Euclidean distance formula: CE=(xE1)2+(yE0)2|CE| = \sqrt{(x_E - 1)^2 + (y_E - 0)^2} If coordinates of point E are known, substitute them in; if EE is at (xE,yE)(x_E, y_E), we can resolve to get the length.

Step 5

Determine the values of x, for which f(x), g(x) < 0.

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Answer

To find the x-values for which both f(x)f(x) and g(x)g(x) are less than 0:

  1. Analyze f(x)<0f(x) < 0. Already established intercepts at A(-3, 0) and B(1, 0) give us the interval (3,1)(-3, 1) where f(x)f(x) is negative.
  2. For g(x)<0g(x) < 0, we need to set mx+c<0mx + c < 0 and solve the linear inequality using known coordinates. Thus identify the overlapping intervals from both inequalities found.

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