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In die diagram is die grafieke van $f(x)=2 ext{sin} ext{}2x$ en $g(x)=- ext{cos}(x+45^{ ext{o}})$ vir die interval $x ext{ e } [0^{ ext{o}}; 180^{ ext{o}}]$ gesketst - NSC Mathematics - Question 6 - 2023 - Paper 2

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In-die-diagram-is-die-grafieke-van-$f(x)=2-ext{sin}-ext{}2x$-en-$g(x)=--ext{cos}(x+45^{-ext{o}})$-vir-die-interval-$x--ext{-e-}-[0^{-ext{o}};-180^{-ext{o}}]$-gesketst-NSC Mathematics-Question 6-2023-Paper 2.png

In die diagram is die grafieke van $f(x)=2 ext{sin} ext{}2x$ en $g(x)=- ext{cos}(x+45^{ ext{o}})$ vir die interval $x ext{ e } [0^{ ext{o}}; 180^{ ext{o}}]$ geskets... show full transcript

Worked Solution & Example Answer:In die diagram is die grafieke van $f(x)=2 ext{sin} ext{}2x$ en $g(x)=- ext{cos}(x+45^{ ext{o}})$ vir die interval $x ext{ e } [0^{ ext{o}}; 180^{ ext{o}}]$ gesketst - NSC Mathematics - Question 6 - 2023 - Paper 2

Step 1

Skryf die periode van f neer.

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Answer

Die periode van f(x)=2extsin(2x)f(x) = 2 ext{sin}(2x) is 180exto180^{ ext{o}}.

Step 2

Bepaal die waardeverzameling van g in die interval x e [0°; 180°].

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Answer

Die waardeverzameling van g(x)=extcos(x+45exto)g(x) = - ext{cos}(x + 45^{ ext{o}}) in die interval [0exto;180exto][0^{ ext{o}}; 180^{ ext{o}}] is yexte[1;1]y ext{ e } [-1; 1].

Step 3

Bepaal die waardes van x, in die interval x e [0°; 180°], waarvoor:

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Answer

6.3.1 f(x)extg(x)>0f(x) ext{g}(x)>0: Die waardes van xx is in die interval (45exto;90exto)(45^{ ext{o}}; 90^{ ext{o}}).

6.3.2 f(x)+1>0f(x)+1>0: Die waardes van xx is in die interval [105exto;165exto][105^{ ext{o}}; 165^{ ext{o}}].

Step 4

Bepaal die waarde(s) van k in die interval x e [0°; 180°].

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Answer

Die waarde(s) van kk wanneer p(x)=f(x)p(x)=-f(x) is k=15extok=15^{ ext{o}} of k=75extok=75^{ ext{o}}.

Step 5

Bepaal die vergelyking van h.

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Answer

Die vergelyking van hh is h(x)=extcos(x+90exto)h(x)=- ext{cos}(x+90^{ ext{o}}), wat ook geskryf kan word as h(x)=extsin(x)h(x)= ext{sin}(x).

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