Beskuif die kwadratiese getalpatroon: -145; -122; -101; .. - NSC Mathematics - Question 3 - 2021 - Paper 1
Question 3
Beskuif die kwadratiese getalpatroon: -145; -122; -101; ...
3.1 Skryf die waarde van T₄ neer.
3.2 Toon dat die algemene term van hierdie getalpatroon Tₙ = -n² + 26... show full transcript
Worked Solution & Example Answer:Beskuif die kwadratiese getalpatroon: -145; -122; -101; .. - NSC Mathematics - Question 3 - 2021 - Paper 1
Step 1
Skryf die waarde van T₄ neer.
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Answer
To find T₄, we use the general term formula:
Tₙ = -n² + 26n - 170.
So, for n = 4:
T₄ = -4² + 26(4) - 170
= -16 + 104 - 170
= -82.
Step 2
Toon dat die algemene term van hierdie getalpatroon Tₙ = -n² + 26n - 170 is.
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Answer
To show that the general term is valid, we calculate based on the pattern:
The first term T₁ = -145 can be represented as:
a = -145,
b = 26,
c = -170.
Using the general term Tₙ = an² + bn + c:
We find:
a = -1, b = 26, c = -170 leading to Tₙ = -n² + 26n - 170.
Step 3
Tussen watTE TWEWE terme van hierdie kwadratiese getalpatroon sal daar 'n verskil van -121 wees?
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Answer
To find between which two terms this difference occurs, set up the equation:
Tₘ - Tₙ = -121.
Substituting the general term:
(-m² + 26m - 170) - (-n² + 26n - 170) = -121.
This simplifies to:
2n - 2m = 121,
which results in:
n = 73, thus between T₃ and T₄.
Step 4
Watter waarde moet by elke term in die getalpatroon gevegt word sodan die waarde van die grootste term in die nuwe kwadratiese getalpatroon wat gevorm word, 1 sal wees?
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Answer
Let x be the value added to each term.
Using T'ₙ = Tₙ + x:
To find when the largest term becomes 1, set:
-(-n² + 26n - 170) + x = 1.
Solving gives:
We find x should be equal to 13, so the equation becomes:
T₃ + 2 = 1 yields:
T₃ = -1 giving the steady increase required.