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In the diagram below, the graph of $f(x) = an(x - 45^ ext{o})$ is drawn for the interval $x ext{ } ext{ } ext{for } [ -90^ ext{o}, 180^ ext{o}].$ 6.1 Write down the period of $f$ - NSC Mathematics - Question 6 - 2023 - Paper 2

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In-the-diagram-below,-the-graph-of-$f(x)-=--an(x---45^-ext{o})$-is-drawn-for-the-interval-$x--ext{-}--ext{-}--ext{for-}-[--90^-ext{o},-180^-ext{o}].$--6.1-Write-down-the-period-of-$f$-NSC Mathematics-Question 6-2023-Paper 2.png

In the diagram below, the graph of $f(x) = an(x - 45^ ext{o})$ is drawn for the interval $x ext{ } ext{ } ext{for } [ -90^ ext{o}, 180^ ext{o}].$ 6.1 Write down... show full transcript

Worked Solution & Example Answer:In the diagram below, the graph of $f(x) = an(x - 45^ ext{o})$ is drawn for the interval $x ext{ } ext{ } ext{for } [ -90^ ext{o}, 180^ ext{o}].$ 6.1 Write down the period of $f$ - NSC Mathematics - Question 6 - 2023 - Paper 2

Step 1

Write down the period of $f$

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Answer

The period of the function f(x)=an(x45exto)f(x) = an(x - 45^ ext{o}) is 180exto180^ ext{o}.

Step 2

Draw the graph of $g(x) = - ext{cos}(2x)$ for the interval $x ext{ for } [-90^ ext{o}, 180^ ext{o}]$

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Answer

The graph of g(x)g(x) is a cosine wave reflected over the x-axis, with its amplitude equal to 1 and a period of 90exto90^ ext{o}. It will intercept the x-axis at multiples of 45exto45^ ext{o} and reach its maximum at x=90extox = -90^ ext{o} and minimum at x=0x = 0, shown clearly across the specified range.

Step 3

Write down the range of $g$

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Answer

The range of g(x)=extcos(2x)g(x) = - ext{cos}(2x) is between [1,1][-1, 1], inclusive.

Step 4

Determine the equation of $h$ in its simplest form

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Answer

If g(x)g(x) is shifted 45exto45^ ext{o} to the left, the equation becomes h(x)=extcos(2(x+45exto))=extcos(2x+90exto)h(x) = - ext{cos}(2(x + 45^ ext{o})) = - ext{cos}(2x + 90^ ext{o}). This simplifies to h(x)=extsin(2x)h(x) = ext{sin}(2x).

Step 5

Use the graph(s) to determine the values of $x$ in the interval $[-90^ ext{o}, 90^ ext{o}]$ for which $f(x) > 1$

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Answer

The values of xx for which f(x)>1f(x) > 1 can be found in the interval xextfor[90exto,45exto)extand(45exto,90exto]x ext{ for } [-90^ ext{o}, -45^ ext{o}) ext{ and } (45^ ext{o}, 90^ ext{o}].

Step 6

Use the graph(s) to determine the values of $x$ in the interval $[-90^ ext{o}, 90^ ext{o}]$ for which $2 ext{cos}(2x) - 1 > 0$

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Answer

Solving 2extcos(2x)1>02 ext{cos}(2x) - 1 > 0 gives ext{cos}(2x) > rac{1}{2}, which corresponds to 2xextin[60exto,60exto]2x ext{ in } [-60^ ext{o}, 60^ ext{o}]. Therefore, the values of xx in the specified interval are in [30exto,30exto][-30^ ext{o}, 30^ ext{o}].

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