SimpleStudy Schools Book a Demo We can give expert advice on our plans and what will be the best option for your school.
Parents Pricing Home NSC Mechanical Technology Automotive Basic calculations 7.1 Define the term compression ratio of an engine
7.1 Define the term compression ratio of an engine - NSC Mechanical Technology Automotive - Question 7 - 2019 - Paper 1 Question 7
View full question 7.1 Define the term compression ratio of an engine.
7.2 The bore and stroke of an engine are 84 mm and 90 mm respectively and they have a compression ratio of 8,5 :... show full transcript
View marking scheme Worked Solution & Example Answer:7.1 Define the term compression ratio of an engine - NSC Mechanical Technology Automotive - Question 7 - 2019 - Paper 1
Define the term compression ratio of an engine. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The compression ratio of an engine is defined as the ratio between the total volume of a cylinder when the piston is at bottom dead center (BDC) to the volume of the charge in a cylinder when the piston is at top dead center (TDC).
The swept volume. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The swept volume (SV) of an engine can be calculated using the formula:
SV = rac{ ext{π}}{4} imes D^2 imes L
Where:
D is the bore diameter (84 mm or 0.084 m)
L is the stroke length (90 mm or 0.090 m)
Substituting the values:
SV = rac{ ext{π}}{4} imes (0.084)^2 imes 0.090 = 0.00049776 ext{ m}^3
Converting to cm³:
S V = 497.76 e x t c m 3 SV = 497.76 ext{ cm}^3 S V = 497.76 e x t c m 3
The original clearance volume in cm3. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
To find the original clearance volume (CV), we can use the formula relating the compression ratio (CR), swept volume (SV), and clearance volume (CV):
CR = rac{SV + CV}{CV}
Given: CR = 8.5 and SV = 497.76 cm³,
Rearranging the formula:
CV = rac{SV}{CR - 1}
Substituting the values:
CV = rac{497.76}{8.5 - 1} = 66.50 ext{ cm}^3
What would be the new bore diameter, if the clearance volume remains unchanged? Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
To find the new bore diameter (D) when the compression ratio is increased to 9.5:1, we keep the clearance volume the same:
Using the formula:
CR = rac{SV + CV}{CV}
We have:
CV = 66.50 cm³
New CR = 9.5
The swept volume SV remains the same (497.76 cm³).
Rearranging and solving for D:
D^2 = rac{4 imes SV imes (CR - 1)}{ ext{π} imes L}
Substituting:
D = rac{ ext{√}(4 imes 497.76 imes (9.5 - 1))}{ ext{π} imes 90} ext{mm}
This simplifies to approximately 89.4 mm.
Torque. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Torque (T) can be calculated using the formula:
T = e x t F o r c e i m e s e x t r a d i u s T = ext{Force} imes ext{radius} T = e x t F orce im ese x t r a d i u s
Where:
Force = Balance reading × g = 125 kg × 10 = 1250 N
radius = Brake arm length = 300 mm = 0.3 m.
So,
T = 1250 i m e s 0.3 = 375 e x t N m T = 1250 imes 0.3 = 375 ext{ Nm} T = 1250 im es 0.3 = 375 e x t N m
Indicated power. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Indicated Power (IP) can be calculated using the formula:
I P = e x t P i m e s e x t L i m e s A i m e s N i m e s n IP = ext{P} imes ext{L} imes A imes N imes n I P = e x t P im ese x t L im es A im es N im es n
Where:
P = Mean effective pressure = 950 kPa = 950000 Pa
L = Stroke length in meters = 140 mm = 0.14 m
A = Area of piston = A = rac{ ext{π} imes D^2}{4}
N = Crankshaft revolutions per minute = 2400 r/min, converted to power strokes per second = 2400 / 60 = 40 power strokes/s
n = number of cylinders = 4.
Calculate A:
ightarrow ext{Convert to } cm^2$$
Plugging the values:
$$IP = 950000 imes 0.14 imes 11.31 imes 10^{-3} imes 40
ightarrow $$ giving approximately 120.34 kW.
Brake power. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Brake Power (BP) can be calculated using the formula:
B P = 2 i m e s e x t π i m e s N i m e s T BP = 2 imes ext{π} imes N imes T BP = 2 im ese x t π im es N im es T
Substituting the known values:
B P = 2 i m e s e x t π i m e s 40 i m e s 375 BP = 2 imes ext{π} imes 40 imes 375 BP = 2 im ese x t π im es 40 im es 375
Calculating this gives approximately 94.25 kW.
Mechanical efficiency. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Mechanical Efficiency (ME) can be calculated using the formula:
ext{ME} = rac{BP}{IP} imes 100 ext{%}
Substituting the values:
ightarrow $$ gives approximately 78.32%. Join the NSC students using SimpleStudy...97% of StudentsReport Improved Results
98% of StudentsRecommend to friends
100,000+ Students Supported
1 Million+ Questions answered
;© 2025 SimpleStudy. All rights reserved