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7.1 Define the term compression ratio of an engine - NSC Mechanical Technology Automotive - Question 7 - 2019 - Paper 1

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7.1 Define the term compression ratio of an engine. 7.2 The bore and stroke of an engine are 84 mm and 90 mm respectively and they have a compression ratio of 8,5 :... show full transcript

Worked Solution & Example Answer:7.1 Define the term compression ratio of an engine - NSC Mechanical Technology Automotive - Question 7 - 2019 - Paper 1

Step 1

Define the term compression ratio of an engine.

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Answer

The compression ratio of an engine is defined as the ratio between the total volume of a cylinder when the piston is at bottom dead center (BDC) to the volume of the charge in a cylinder when the piston is at top dead center (TDC).

Step 2

The swept volume.

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Answer

The swept volume (SV) of an engine can be calculated using the formula:

SV = rac{ ext{π}}{4} imes D^2 imes L

Where:

  • D is the bore diameter (84 mm or 0.084 m)
  • L is the stroke length (90 mm or 0.090 m)

Substituting the values:

SV = rac{ ext{π}}{4} imes (0.084)^2 imes 0.090 = 0.00049776 ext{ m}^3

Converting to cm³:

SV=497.76extcm3SV = 497.76 ext{ cm}^3

Step 3

The original clearance volume in cm3.

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Answer

To find the original clearance volume (CV), we can use the formula relating the compression ratio (CR), swept volume (SV), and clearance volume (CV):

CR = rac{SV + CV}{CV}

Given: CR = 8.5 and SV = 497.76 cm³,

Rearranging the formula:

CV = rac{SV}{CR - 1}

Substituting the values:

CV = rac{497.76}{8.5 - 1} = 66.50 ext{ cm}^3

Step 4

What would be the new bore diameter, if the clearance volume remains unchanged?

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Answer

To find the new bore diameter (D) when the compression ratio is increased to 9.5:1, we keep the clearance volume the same:

Using the formula:

CR = rac{SV + CV}{CV}

We have:

  • CV = 66.50 cm³
  • New CR = 9.5
  • The swept volume SV remains the same (497.76 cm³).

Rearranging and solving for D:

D^2 = rac{4 imes SV imes (CR - 1)}{ ext{π} imes L}

Substituting:

D = rac{ ext{√}(4 imes 497.76 imes (9.5 - 1))}{ ext{π} imes 90} ext{mm}

This simplifies to approximately 89.4 mm.

Step 5

Torque.

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Answer

Torque (T) can be calculated using the formula:

T=extForceimesextradiusT = ext{Force} imes ext{radius}

Where:

  • Force = Balance reading × g = 125 kg × 10 = 1250 N
  • radius = Brake arm length = 300 mm = 0.3 m.

So,

T=1250imes0.3=375extNmT = 1250 imes 0.3 = 375 ext{ Nm}

Step 6

Indicated power.

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Answer

Indicated Power (IP) can be calculated using the formula:

IP=extPimesextLimesAimesNimesnIP = ext{P} imes ext{L} imes A imes N imes n

Where:

  • P = Mean effective pressure = 950 kPa = 950000 Pa
  • L = Stroke length in meters = 140 mm = 0.14 m
  • A = Area of piston = A = rac{ ext{π} imes D^2}{4}
  • N = Crankshaft revolutions per minute = 2400 r/min, converted to power strokes per second = 2400 / 60 = 40 power strokes/s
  • n = number of cylinders = 4.

Calculate A:

ightarrow ext{Convert to } cm^2$$ Plugging the values: $$IP = 950000 imes 0.14 imes 11.31 imes 10^{-3} imes 40 ightarrow $$ giving approximately 120.34 kW.

Step 7

Brake power.

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Answer

Brake Power (BP) can be calculated using the formula:

BP=2imesextπimesNimesTBP = 2 imes ext{π} imes N imes T

Substituting the known values:

BP=2imesextπimes40imes375BP = 2 imes ext{π} imes 40 imes 375

Calculating this gives approximately 94.25 kW.

Step 8

Mechanical efficiency.

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Answer

Mechanical Efficiency (ME) can be calculated using the formula:

ext{ME} = rac{BP}{IP} imes 100 ext{%}

Substituting the values:

ightarrow $$ gives approximately 78.32%.

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