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5.1 A spur gear with 118 teeth must be cut on a universal milling machine - NSC Mechanical Technology Automotive - Question 5 - 2017 - Paper 1

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5.1 A spur gear with 118 teeth must be cut on a universal milling machine. Calculate the indexing required to cut this gear with the help of a Cincinnati dividing he... show full transcript

Worked Solution & Example Answer:5.1 A spur gear with 118 teeth must be cut on a universal milling machine - NSC Mechanical Technology Automotive - Question 5 - 2017 - Paper 1

Step 1

5.1 A spur gear with 118 teeth must be cut on a universal milling machine. Calculate the indexing required to cut this gear with the help of a Cincinnati dividing head.

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Answer

To calculate the indexing, we utilize the formula:

extIndexing=40n ext{Indexing} = \frac{40}{n}

Where:

  • n = number of divisions.
  • For 118 teeth, we set n as follows:
extIndexing=40118=0.339ext(approximately) ext{Indexing} = \frac{40}{118} = 0.339 ext{ (approximately)}

The result means you can set up the dividing head for 40 / n divisions. We confirm the setup has no full turns with 20 holes in a 59-hole plate.

Step 2

5.2 Use simple line sketches to explain the difference between up-cut milling and down-cut milling on a milling machine. Indicate the work-piece feed and cutter rotation.

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Answer

Up-cut Milling

  • The cutter rotates counterclockwise.
  • The work-piece feed moves against the direction of cutter rotation.
  • A sketch would show the cutter pulling the material up, resulting in a slightly smoother finish but creating a risk of chatter.

Down-cut Milling

  • The cutter rotates clockwise.
  • The work-piece feed moves in the same direction as the cutter rotation.
  • A sketch would show the cutter pushing the material down, providing a better surface finish but can cause more tool wear.

Step 3

5.3.1 The width of the key:

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Answer

The width of the key can be calculated using:

extWidth=D4=1024=25.5extmm ext{Width} = \frac{D}{4} = \frac{102}{4} = 25.5 ext{ mm}

Step 4

5.3.2 The thickness of the key:

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The thickness of the key can be calculated using:

extThickness=D6=1026=17extmm ext{Thickness} = \frac{D}{6} = \frac{102}{6} = 17 ext{ mm}

Step 5

5.3.3 The length of the key:

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Answer

The length of the key is:

extLength=D×1.5=102×1.5=153extmm ext{Length} = D \times 1.5 = 102 \times 1.5 = 153 ext{ mm}

Step 6

5.3.4 The thickness of the key at the smaller end:

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Answer

The thickness at the smaller end can be determined using:

extThicknessatsmallerend=TL100=17153100=15.47extmm ext{Thickness at smaller end} = T - \frac{L}{100} = 17 - \frac{153}{100} = 15.47 ext{ mm}

Step 7

5.4.1 Addendum

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Answer

Addendum = m = 3 mm

Step 8

5.4.2 Dedendum

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Answer

Dedendum can be calculated as:

extDedendum=1.157m=1.157×3=3.471extmm ext{Dedendum} = 1.157 m = 1.157 \times 3 = 3.471 ext{ mm}

Step 9

5.4.3 Clearance

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Answer

Clearance = 0.157 m = 0.157 \times 3 = 0.471 ext{ mm}

Step 10

5.4.4 Pitch circle diameter

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Answer

Pitch circle diameter (PCD) can be calculated using:

OD=PCD+2m=180+2(3)=186extmm\text{OD} = \text{PCD} + 2m = 180 + 2(3) = 186 ext{ mm}

Step 11

5.4.5 Outside diameter

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Answer

Outside diameter can be calculated as:

OD=180+2(3)=186extmm\text{OD} = 180 + 2(3) = 186 ext{ mm}

Step 12

5.4.6 Cutting depth

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Answer

The cutting depth is:

Cutting depth=2.157+2.25=6.47extmm\text{Cutting depth} = 2.157 + 2.25 = 6.47 ext{ mm}

Step 13

5.4.7 Circular pitch

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Answer

Circular pitch can be calculated using:

Circular pitch=3×m×π=3×3×π9.43extmm\text{Circular pitch} = 3 \times m \times \pi = 3 \times 3 \times \pi \approx 9.43 ext{ mm}

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