5.1 A spur gear with 118 teeth must be cut on a universal milling machine - NSC Mechanical Technology Automotive - Question 5 - 2017 - Paper 1
Question 5
5.1 A spur gear with 118 teeth must be cut on a universal milling machine. Calculate the indexing required to cut this gear with the help of a Cincinnati dividing he... show full transcript
Worked Solution & Example Answer:5.1 A spur gear with 118 teeth must be cut on a universal milling machine - NSC Mechanical Technology Automotive - Question 5 - 2017 - Paper 1
Step 1
5.1 A spur gear with 118 teeth must be cut on a universal milling machine. Calculate the indexing required to cut this gear with the help of a Cincinnati dividing head.
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Answer
To calculate the indexing, we utilize the formula:
extIndexing=n40
Where:
n = number of divisions.
For 118 teeth, we set n as follows:
extIndexing=11840=0.339ext(approximately)
The result means you can set up the dividing head for 40 / n divisions. We confirm the setup has no full turns with 20 holes in a 59-hole plate.
Step 2
5.2 Use simple line sketches to explain the difference between up-cut milling and down-cut milling on a milling machine. Indicate the work-piece feed and cutter rotation.
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Up-cut Milling
The cutter rotates counterclockwise.
The work-piece feed moves against the direction of cutter rotation.
A sketch would show the cutter pulling the material up, resulting in a slightly smoother finish but creating a risk of chatter.
Down-cut Milling
The cutter rotates clockwise.
The work-piece feed moves in the same direction as the cutter rotation.
A sketch would show the cutter pushing the material down, providing a better surface finish but can cause more tool wear.
Step 3
5.3.1 The width of the key:
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Answer
The width of the key can be calculated using:
extWidth=4D=4102=25.5extmm
Step 4
5.3.2 The thickness of the key:
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The thickness of the key can be calculated using:
extThickness=6D=6102=17extmm
Step 5
5.3.3 The length of the key:
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The length of the key is:
extLength=D×1.5=102×1.5=153extmm
Step 6
5.3.4 The thickness of the key at the smaller end:
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The thickness at the smaller end can be determined using: