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A spur gear has a pitch-circle diameter of 126 mm with 42 teeth - NSC Mechanical Technology Fitting and Machining - Question 6 - 2019 - Paper 1

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A spur gear has a pitch-circle diameter of 126 mm with 42 teeth. Calculate the following: 6.1.1 Module 6.1.2 Working depth 6.1.3 Cutting depth 6.2 Calculate the... show full transcript

Worked Solution & Example Answer:A spur gear has a pitch-circle diameter of 126 mm with 42 teeth - NSC Mechanical Technology Fitting and Machining - Question 6 - 2019 - Paper 1

Step 1

6.1.1 Module

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Answer

To calculate the module of the spur gear, we use the formula:

Module=PCDTModule = \frac{PCD}{T}

Where PCD is the pitch-circle diameter and T is the number of teeth.

Substituting the given values:

Module=126 mm42=3 mmModule = \frac{126 \text{ mm}}{42} = 3 \text{ mm}

Thus, the module is 3 mm.

Step 2

6.1.2 Working depth

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The working depth (WD) can be calculated using the formula:

WD=2×mWD = 2 \times m

Where m is the module. Substituting the previously calculated module:

WD=2×3 mm=6 mmWD = 2 \times 3 \text{ mm} = 6 \text{ mm}

Therefore, the working depth is 6 mm.

Step 3

6.1.3 Cutting depth

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The cutting depth can be calculated as:

Cutting depth=2.157×mCutting\ depth = 2.157 \times m

Using the module value:

Cutting depth=2.157×3 mm=6.471 mmCutting\ depth = 2.157 \times 3 \text{ mm} = 6.471 \text{ mm}

Alternatively, it can also be given in terms of:

Cutting depth=2.25×m=2.25×3 mm=6.75 mmCutting\ depth = 2.25 \times m = 2.25 \times 3 \text{ mm} = 6.75 \text{ mm}

Thus, the cutting depth can be either 6.471 mm or 6.75 mm.

Step 4

6.2 Calculate the required angular indexing for an angle of 34°

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Answer

To find the required angular indexing, we use the formula:

Indexing=34°9°=349=3.78ext(approximately3fullturnswithremainder)Indexing = \frac{34°}{9°} = \frac{34}{9} = 3.78 \\ ext{(approximately 3 full turns with remainder)}

This means that after 3 full turns, the next step involves finding the corresponding hole count using the ratio:

N=34° to 9°34° times4254=3 holesext(foratotalof3fullturnsand42holesonthe54holecircle)N = 34° \text{ to } 9° \rightarrow 34°\ times \frac{42}{54} = 3\text{ holes} \\ ext{(for a total of 3 full turns and 42 holes on the 54 hole circle)}

Thus, angular indexing for this angle results in 3 full turns and 42 holes.

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