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5.1 A taper with a length of 60 mm and a large diameter of 40 mm and a small diameter of 31.6 mm needs to be cut on a lathe using the compound slide method - NSC Mechanical Technology Fitting and Machining - Question 5 - 2020 - Paper 1

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5.1-A-taper-with-a-length-of-60-mm-and-a-large-diameter-of-40-mm-and-a-small-diameter-of-31.6-mm-needs-to-be-cut-on-a-lathe-using-the-compound-slide-method-NSC Mechanical Technology Fitting and Machining-Question 5-2020-Paper 1.png

5.1 A taper with a length of 60 mm and a large diameter of 40 mm and a small diameter of 31.6 mm needs to be cut on a lathe using the compound slide method. 5.1.1 D... show full transcript

Worked Solution & Example Answer:5.1 A taper with a length of 60 mm and a large diameter of 40 mm and a small diameter of 31.6 mm needs to be cut on a lathe using the compound slide method - NSC Mechanical Technology Fitting and Machining - Question 5 - 2020 - Paper 1

Step 1

5.1.1 Draw a neat sketch of the taper and label it.

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Answer

To draw the taper, sketch a right trapezoid that represents the taper profile. The larger diameter (40 mm) should be at the left, attached to the 60 mm length, tapering down to the smaller diameter (31.6 mm) at the right. Label the dimensions clearly: 40 mm, 31.6 mm, and 60 mm.

Step 2

5.1.2 Calculate the included angle.

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Answer

The included angle \( heta\) can be calculated using the formula:

tan(θ)=Dd2L\tan(\theta) = \frac{D - d}{2L}

Where:

  • D = large diameter = 40 mm
  • d = small diameter = 31.6 mm
  • L = length = 60 mm

Plugging in the values:

tan(θ)=4031.62×60=8.4120=0.07\tan(\theta) = \frac{40 - 31.6}{2 \times 60} = \frac{8.4}{120} = 0.07

To find the angle, take the arctangent:

θ=tan1(0.07)4.004\theta = \tan^{-1}(0.07) \approx 4.004^{\circ}.

Step 3

5.1.3 At what degree do you need to set the compound slide to cut this taper?

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Answer

You need to set the compound slide to half of the included angle calculated above:

Angle=4.00422.002\text{Angle} = \frac{4.004^{\circ}}{2} \approx 2.002^{\circ}.

Step 4

5.2 Calculate the width and length of a parallel key suitable for a 30 mm diameter shaft.

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Answer

The width (W) of the parallel key can be calculated as:

W=D4=304=7.5 mmW = \frac{D}{4} = \frac{30}{4} = 7.5 \text{ mm}

The length (L) of the parallel key is calculated using:

L=1.5×D=1.5×30=45 mmL = 1.5 \times D = 1.5 \times 30 = 45 \text{ mm}.

Step 5

5.3 A 15 mm wide keyway must be cut on a work piece with a diameter of 60 mm. The rule and square method is used to centre the cutter. Calculate the distance X shown in FIGURE 5.3.

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Answer

To calculate the distance X:

X=diameter of workpiecethickness of cutter2X = \frac{\text{diameter of workpiece} - \text{thickness of cutter}}{2}

Given:

  • Diameter of workpiece = 60 mm
  • Thickness of cutter = 15 mm

We can substitute these values:

X=60152=452=22.5 mmX = \frac{60 - 15}{2} = \frac{45}{2} = 22.5 \text{ mm}.

Step 6

5.4 Use a neat, labelled sketch to explain straddle milling.

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Answer

Straddle milling is a method where two or more milling cutters are mounted on the same arbor to mill two opposite sides of a workpiece simultaneously. In your sketch, label the following components:

  • Arbour: the shaft on which the cutters are mounted.
  • Milling cutters: the cutting tools that do the actual milling.
  • Workpiece: the material being machined. Ensure the sketch clearly shows that cutters are on both sides of the workpiece, maximizing efficiency in machining.

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