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Parents Pricing Home NSC Mechanical Technology Fitting and Machining ISO metric V tread 6.1 A spur gear with 50 teeth has a module of 3
6.1 A spur gear with 50 teeth has a module of 3 - NSC Mechanical Technology Fitting and Machining - Question 6 - 2018 - Paper 1 Question 6
View full question 6.1 A spur gear with 50 teeth has a module of 3. Calculate the cordal tooth thickness of the gear teeth.
6.2 Calculate the required simple indexing to cut a gear wi... show full transcript
View marking scheme Worked Solution & Example Answer:6.1 A spur gear with 50 teeth has a module of 3 - NSC Mechanical Technology Fitting and Machining - Question 6 - 2018 - Paper 1
Calculate the cordal tooth thickness of the gear teeth. Only available for registered users.
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To find the cordal tooth thickness (t c t_c t c ), use the formula:$
t_c = rac{T}{2} imes ext{sin} rac{90°}{T}
$
Where:
Plugging in the values:
egin{align*}
ext{Using } T = 50\
\
t_c = rac{50}{2} imes ext{sin} rac{90°}{50} = 4.71 ext{ mm}
ext{or}
\
t_c = PCD imes ext{sin} rac{90°}{T} \
= rac{150}{50} imes 0.03141 \
= 4.71 ext{ mm}
ext{So the cordal tooth thickness is approximately 4.71 mm.}
ext{Final Answer: } t_c ext{ = 4.71 mm}
Calculate the required simple indexing. Only available for registered users.
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To calculate simple indexing for a gear with 13 teeth,
Use the formula for simple indexing:
ext{Simple indexing } = 40 imes rac{N}{ ext{number of turns}}
With N = 40 and the number of teeth = 13:
After determining parameters, set up for 39 hole circle as follows:
= 3 e x t f u l l t u r n s a n d 3 h o l e s i n a 39 h o l e c i r c l e . = 3 ext{ full turns and 3 holes in a 39 hole circle.} = 3 e x t f u llt u r n s an d 3 h o l es ina 39 h o l ec i rc l e .
The differential indexing required (Choose 125 teeth.) Only available for registered users.
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For differential indexing:
ext{Indexing } = rac{40}{40} - rac{n}{N} \
N = 127, ext{ thus = } rac{40}{40} - rac{127}{125}
Solving this gives:
Required differential indexing for 125 teeth is 8 8 8 holes on the 25 25 25 hole circle.
The change gears required Only available for registered users.
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The change gears can be calculated by:
D_r = rac{A_n imes D}{40} \
D_r = 125 - 127 imes rac{40}{125}
Solving, we find:
Change gears required = 64 ratios 100.
The direction of rotation of the index plate in relation to the index crank handle. Only available for registered users.
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The index plate will turn in the opposite direction to that of the index crank handle.
Calculate distance X between the rollers in FIGURE 6.4. Only available for registered users.
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To calculate distance X X X :
Use the geometric relationships:
x = 150 + 2(AB) - 2(CD) - 2r\
Here, with given values and utilizing tan properties:
= 150 + 2 ( 20.21 ) − 2 ( 25.98 ) − 30 = 108.454 e x t m m = 150 + 2(20.21) - 2(25.98) - 30 = 108.454 ext{ mm} = 150 + 2 ( 20.21 ) − 2 ( 25.98 ) − 30 = 108.454 e x t mm
Give TWO reasons why a work piece must be balanced on a centre lathe when a face plate is used. Only available for registered users.
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To prevent unnecessary bearing loads.
To avoid excessive vibrations.
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