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A spur gear, with a pitch-circle diameter of 168 mm and 42 teeth, is needed for a gearbox - NSC Mechanical Technology Fitting and Machining - Question 6 - 2022 - Paper 1

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A spur gear, with a pitch-circle diameter of 168 mm and 42 teeth, is needed for a gearbox. Calculate the following: 6.1.1 Module 6.1.2 Circular pitch 6.1.3 Outside ... show full transcript

Worked Solution & Example Answer:A spur gear, with a pitch-circle diameter of 168 mm and 42 teeth, is needed for a gearbox - NSC Mechanical Technology Fitting and Machining - Question 6 - 2022 - Paper 1

Step 1

6.1.1 Module

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Answer

The module of a spur gear can be calculated using the formula:

ext{Module} = rac{ ext{Pitch Circle Diameter (PCD)}}{ ext{Number of teeth (T)}}

Substituting the provided values:

ext{Module} = rac{168 ext{ mm}}{42} = 4 ext{ mm}

Step 2

6.1.2 Circular pitch

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Answer

The circular pitch can be calculated using the formula:

extCP=extModuleimesextπ=4extmmimesextπ ext{CP} = ext{Module} imes ext{π} = 4 ext{ mm} imes ext{π}

Calculating this gives:

extCPhickapprox12.57extmm ext{CP} hickapprox 12.57 ext{ mm}

Step 3

6.1.3 Outside diameter

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Answer

The outside diameter can be calculated using the formula:

extOD=extModuleimes(T+2) ext{OD} = ext{Module} imes (T + 2)

Substituting the values:

extOD=4extmmimes(42+2)=4extmmimes44=176extmm ext{OD} = 4 ext{ mm} imes (42 + 2) = 4 ext{ mm} imes 44 = 176 ext{ mm}

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