Willy is 'n masjienoperateur om 'n regguitandrat met 'n steeksirkeldiameter van 120 mm en 'n module van 3 te sny - NSC Mechanical Technology Fitting and Machining - Question 6 - 2023 - Paper 1
Question 6
Willy is 'n masjienoperateur om 'n regguitandrat met 'n steeksirkeldiameter van 120 mm en 'n module van 3 te sny.
Bereken die volgende:
6.1.1 Aantal tande
6.1.2 De... show full transcript
Worked Solution & Example Answer:Willy is 'n masjienoperateur om 'n regguitandrat met 'n steeksirkeldiameter van 120 mm en 'n module van 3 te sny - NSC Mechanical Technology Fitting and Machining - Question 6 - 2023 - Paper 1
Step 1
6.1.1 Aantal tande
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Answer
Om die aantal tande van die regguitandrat te bereken, gebruik ons die formule:
Tande=TSSD=3120=40
Dus, die regguitandrat het 40 tande.
Step 2
6.1.2 Dedendum
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Answer
Die dedendum kan bereken word met die formule:
Dedendum=m×1,157=3×1,157=3,471mm
Dus, die dedendum is 3,47 mm.
Step 3
6.1.3 Buitediameter
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Answer
Die buitendiameter van die tandrad kan bereken word met:
Buitediameter=SSD+2×m=120+2×3=126mm
Die buitendiameter is dus 126 mm.
Step 4
6.1.4 Sirkelsteek
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Answer
Die sirkelsteek kan bereken word met die formule:
SS=m×π=3×π≈9,42mm
Dus, die sirkelsteek is ongeveer 9,42 mm.
Step 5
6.2.1 Die hoek θ
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Answer
Om die hoek θ te bereken, voer die volgende berekening uit:
θ=2(166,96−112,32−2(10))=17,32mm
Met die tangens:
Tanα=ACBC=17,3210
Daarna is die waarde van α as:
α=30°⇒θ=60°
Step 6
6.2.2 Minimum wydte (w) afstand van die swaelstert
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Answer
Die minimum wydte kan bereken word met:
Tan(2θ)=ADDE
Deur te omskakel, het ons:
DE=Tan(30°)×AD=Tan(30°)×32=18,48mm
Die wydte w kan bereken word met:
w=166,96−2(DE)=166,96−2(18,48)=130mm
Step 7
6.3.1 Die indeksering wat benodig word
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Answer
Die indeksering kan bereken word met die formule:
Indeksering=N40
Waar:
40=140⇒N=40⇒Indeksering=8gateop′n28−gatsirkel
Step 8
6.3.2 Die wisselratte wat vereis word
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