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6.1 A machinist in a milling workshop is tasked to cut a spur gear with 180 teeth and a module of 2.5 - NSC Mechanical Technology Fitting and Machining - Question 6 - 2023 - Paper 1

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6.1 A machinist in a milling workshop is tasked to cut a spur gear with 180 teeth and a module of 2.5. Calculate the following: 6.1.1 Pitch-circle diameter 6.1.2 De... show full transcript

Worked Solution & Example Answer:6.1 A machinist in a milling workshop is tasked to cut a spur gear with 180 teeth and a module of 2.5 - NSC Mechanical Technology Fitting and Machining - Question 6 - 2023 - Paper 1

Step 1

6.1.1 Pitch-circle diameter

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Answer

To calculate the pitch-circle diameter (PCD) of the spur gear, use the formula:

PCD=m×TPCD = m \times T

Where:

  • mm = module = 2.5
  • TT = number of teeth = 180

Calculating gives:

PCD=2.5×180=450 mmPCD = 2.5 \times 180 = 450 \text{ mm}

Step 2

6.1.2 Dedendum

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Answer

The dedendum can be calculated using the formula:

Dedendum=1.157×mDedendum = 1.157 \times m

Substituting the known values:

Dedendum=1.157×2.5=2.89 mmDedendum = 1.157 \times 2.5 = 2.89 \text{ mm}

Step 3

6.1.3 Outside diameter

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Answer

The outside diameter (OD) of the spur gear can be calculated using:

OD=PCD+2×mOD = PCD + 2 \times m

Substituting the values:

OD=450+2×2.5=455 mmOD = 450 + 2 \times 2.5 = 455 \text{ mm}

Step 4

6.2.1 Maximum width (W) distance of the dovetail

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Answer

To find the maximum width (W), first calculate DE using tangent geometry:

tanθ=DEAD\tan \theta = \frac{DE}{AD}

Given AD=50AD = 50:

DE=tan60×5028.87 mmDE = \tan 60^{\circ} \times 50 \approx 28.87 \text{ mm}

Then:

W=136+2(28.87)=193.74 mmW = 136 + 2(28.87) = 193.74 \text{ mm}

Step 5

6.2.2 Distance (m) between the precision rollers

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Answer

Calculate distance (m) using:

m=W2(AC+R)m = W - 2(AC + R)

With AC=17.32AC = 17.32 and radius R=10R = 10:

m=193.742(17.32+10)ightarrowm139.10 mmm = 193.74 - 2(17.32 + 10) ightarrow m \approx 139.10 \text{ mm}

Step 6

6.3.1 Calculate the indexing that is needed

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Answer

For the indexing required, use:

Indexing=40N=4089×40=24Indexing = \frac{40}{N} = \frac{40}{89} \times 40 = 24

This means 0 full turns and 24 holes on a 54-hole circle.

Step 7

6.3.2 Calculate the change gears that are required

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Answer

Change gears can be calculated using:

DrDn=(An)×40A\frac{D_r}{D_n} = \frac{(A - n) \times 40}{A}

For our scenario, where A=90A = 90:

This gives:

Dr:Dn=4:9extorDr=32,Dn=72D_r : D_n = 4 : 9 ext{ or } D_r = 32, D_n = 72

Step 8

6.4 Describe any TWO constraints/disadvantages

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Answer

  1. Requires specialized machinery: Balancing needs tools and machines specifically designed for the purpose, which increases operational costs.

  2. Difficult to ascertain the exact point of unbalance: Achieving precise balance requires detailed knowledge of the workpiece and operational parameters, making it complex during the balancing process.

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