10.1 'n Twee-gang- vierkantige skroefraadstaaf moet vervaardig word - NSC Mechanical Technology Fitting and Machining - Question 10 - 2021 - Paper 1
Question 10
10.1 'n Twee-gang- vierkantige skroefraadstaaf moet vervaardig word. Die stygings van die skroefraad is 40 mm en die kruindiameter is 85 mm. Die vrylopoek moet 3° w... show full transcript
Worked Solution & Example Answer:10.1 'n Twee-gang- vierkantige skroefraadstaaf moet vervaardig word - NSC Mechanical Technology Fitting and Machining - Question 10 - 2021 - Paper 1
Step 1
10.1.1 Gemiddelde diameter
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Answer
Die gemiddelde diameter kan bereken word met die volgende formule:
Dm=DO−2P
Hier, die buitendiameter (D_O) is 85 mm en die pasiëring is 40 mm met twee gang:
P=240=20 mm
Daarom:
Dm=85−220=75 mm
Step 2
10.1.2 Helikshoek van die skroefraad
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Answer
Die helikshoek van die skroefraad kan bepaal word deur die volgende formule te gebruik:
tan(θ)=πDmlead
Hier is die lead 40 mm:
tan(θ)=π×7540
Berekeningen lei tot:
θ=tan−1(0.169765272)
Hieruit volg:
\theta \approx 9.63° \text{ of } 9°38'
Step 3
10.1.3 Ingryphoek (Voorsnhoek) van die beitel
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Answer
Die ingryphoek of voorsnhoek van die beitel word bereken met:
Leadingtoolangle=90°+helix+clearanceangle
Met die helikshoek 9.63° en vrylopoek 3°:
Leading tool angle=90°+9.63°−3°=77.37° of 77°22′
Step 4
10.1.4 Sleephoek (Nasnhoek) van die beitel
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Answer
Die sleephoek of nasnhoek kan bepaal word met:
Followingtoolangle=90°−helix+clearanceangle
In hierdie geval:
Followingtoolangle=90°−9.63°−3°=96.63° of 96°38′
Step 5
10.2 A–D
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Answer
A. Pitch diameter/mean/effective
B. Helikshoek
C. Pitch / Lead
D. Root/Root length
Step 6
10.3 Gebruik van 'n vierkantige skroefraad
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