Calculate the following:
11.1.1 The area of the ram if the diameter of the cylinder is 110 mm - NSC Mechanical Technology Fitting and Machining - Question 11 - 2023 - Paper 1
Question 11
Calculate the following:
11.1.1 The area of the ram if the diameter of the cylinder is 110 mm.
11.1.2 Force applied on the small piston (plunger).
11.1.3 The disp... show full transcript
Worked Solution & Example Answer:Calculate the following:
11.1.1 The area of the ram if the diameter of the cylinder is 110 mm - NSC Mechanical Technology Fitting and Machining - Question 11 - 2023 - Paper 1
Step 1
11.1.1 The area of the ram if the diameter of the cylinder is 110 mm.
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Answer
To find the area of the ram, we use the formula:
A=4πD2
Substituting the diameter (D = 0.110 m):
A=4π(0.110)2=0.0095m2
Step 2
11.1.2 Force applied on the small piston (plunger).
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Answer
Using the formula for force:
f=AF⋅a
Given F = 350 N and A (area of the plunger) = 0.005 m²:
f=0.0095350×0.005≈184.21N
Step 3
11.1.3 The displacement h of the small piston (plunger) in mm.
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Answer
Using the relationship:
h=aA⋅H
Where H is the area of the ram, and substituting values:
h=0.005m20.0095m2⋅0.025m=0.0475m=47.5mm
Step 4
11.2 What is the purpose of using pressure gauges in a hydraulic system?
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Answer
Pressure gauges serve several purposes:
They help to adjust pressure control valves.
They allow for determining the pressure being exerted.
For safety, as they indicate whether pressure limits are being approached.
They can indicate any leaks present in the system.
Step 5
11.3 State ONE advantage of applying pneumatics in a system.
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Answer
One advantage of pneumatics is that pneumatic tools are typically very environmentally friendly due to their clean operation.
Step 6
11.4.1 The rotational frequency of the driven pulley in r/sec.
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Answer
To find the rotational frequency of the driven pulley, we use:
NDN=DDNNDR×DDR
Substituting values:
NDN=35025×75≈5.36r/sec
Step 7
11.4.2 The belt speed in m.s$^{-1}$.
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Answer
Using the formula for belt speed:
V=DDNDDR×NDR
Substituting values:
V=0.350m0.075m×25≈5.89m/s
Step 8
11.5 What protects a V-belt against sudden loads so that it cannot get damaged?
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Answer
The slippage of the V-belt is what protects it against sudden loads, ensuring the belt does not sustain damage.
Step 9
11.6.1 The rotation frequency of the output shaft in r/min.
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