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Parents Pricing Home NSC Mechanical Technology Welding and Metalwork Basic calculations A brass ring must be manufactured using a 30 x 30 mm square bar
A brass ring must be manufactured using a 30 x 30 mm square bar - NSC Mechanical Technology Welding and Metalwork - Question 5 - 2023 - Paper 1 Question 5
View full question A brass ring must be manufactured using a 30 x 30 mm square bar. The ring has an inside diameter of 870 mm.
Calculate the following:
5.1.1 The mean diameter of the... show full transcript
View marking scheme Worked Solution & Example Answer:A brass ring must be manufactured using a 30 x 30 mm square bar - NSC Mechanical Technology Welding and Metalwork - Question 5 - 2023 - Paper 1
5.1.1 The mean diameter of the ring Only available for registered users.
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To find the mean diameter of the ring, we use the formula:
e x t M e a n D i a m e t e r = e x t I n s i d e D i a m e t e r + e x t P l a t e T h i c k n e s s ext{Mean Diameter} = ext{Inside Diameter} + ext{Plate Thickness} e x t M e an D iam e t er = e x t I n s i d eD iam e t er + e x t Pl a t e T hi c kn ess Given that the inside diameter is 870 mm and the plate thickness is 30 mm:
e x t M e a n D i a m e t e r = 870 e x t m m + 30 e x t m m = 900 e x t m m ext{Mean Diameter} = 870 ext{ mm} + 30 ext{ mm} = 900 ext{ mm} e x t M e an D iam e t er = 870 e x t mm + 30 e x t mm = 900 e x t mm
5.1.2 The mean circumference of the ring Only available for registered users.
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The mean circumference can be calculated using the formula:
e x t M e a n C i r c u m f e r e n c e = e x t π i m e s e x t M e a n D i a m e t e r ext{Mean Circumference} = ext{π} imes ext{Mean Diameter} e x t M e an C i rc u m f ere n ce = e x t π im ese x t M e an D iam e t er Using the mean diameter calculated above:
e x t M e a n C i r c u m f e r e n c e = e x t π i m e s 900 e x t m m e x t M e a n C i r c u m f e r e n c e e x t ( a p p r o x i m a t e l y ) = 2827 e x t m m e x t ( r o u n d e d t o t h e n e a r e s t w h o l e n u m b e r ) ext{Mean Circumference} = ext{π} imes 900 ext{ mm} \\
ext{Mean Circumference} ext{ (approximately)} = 2827 ext{ mm} ext{ (rounded to the nearest whole number)} e x t M e an C i rc u m f ere n ce = e x t π im es 900 e x t mm e x t M e an C i rc u m f ere n ce e x t ( a pp ro x ima t e l y ) = 2827 e x t mm e x t ( ro u n d e d t o t h e n e a res tw h o l e n u mb er )
5.2.1 Square butt Only available for registered users.
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The fusion weld symbol for a square butt joint is represented as:
||
5.2.2 V-groove Only available for registered users.
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The fusion weld symbol for a V-groove joint is represented as:
V
5.2.3 U-butt Only available for registered users.
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The fusion weld symbol for a U-butt joint is represented as:
U
5.2.4 J-butt Only available for registered users.
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The fusion weld symbol for a J-butt joint is represented as:
J
5.2.5 Flare V Only available for registered users.
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The fusion weld symbol for a flare V joint is represented as:
\(\cup\)
5.3.1 Identify the type of joint. Only available for registered users.
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The type of joint identified in the figure is a T-joint.
5.3.2 Identify labels A–G. Only available for registered users.
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The labels are:
A - weld all around
B - site weld
C - fillet weld
D - tail
E - pitch of weld
F - length of weld
G - size of weld
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