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A driver gear on the shaft of an electrical motor has 30 teeth and meshes with a gear on a countershaft which has 80 teeth - NSC Mechanical Technology Welding and Metalwork - Question 9 - 2016 - Paper 1

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Question 9

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A driver gear on the shaft of an electrical motor has 30 teeth and meshes with a gear on a countershaft which has 80 teeth. There is a driver gear with 40 teeth on t... show full transcript

Worked Solution & Example Answer:A driver gear on the shaft of an electrical motor has 30 teeth and meshes with a gear on a countershaft which has 80 teeth - NSC Mechanical Technology Welding and Metalwork - Question 9 - 2016 - Paper 1

Step 1

9.1.1 The rotation frequency of the electrical motor

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Answer

To find the rotation frequency of the electrical motor, we can use the following formula:

N_a = rac{T_b imes N_d}{T_a \times T_c}
Where:

  • TbT_b = Number of teeth on driven gear = 80
  • TaT_a = Number of teeth on driver gear = 30
  • NdN_d = Speed of driven gear = 2 r.s-1
  • TcT_c = Number of teeth on the counter shaft gear = 40

Substituting the values:

Na=80×230×40=8.4N_a = \frac{80 \times 2}{30 \times 40} = 8.4
The rotation frequency of the electrical motor is therefore: Na=1200N_a = 1200 rev/min (or 20 r.p.s).

Step 2

9.1.2 The speed ratio of the gear train

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Answer

The speed ratio can be calculated as follows:

Speed ratio=InputOutput\text{Speed ratio} = \frac{\text{Input}}{\text{Output}}
Where:

  • Input = 80 (driven teeth)
  • Output = 30 (driver teeth)

Substituting the values gives:

Speed ratio=8030=2.67:1\text{Speed ratio} = \frac{80}{30} = 2.67 : 1
This indicates that for every 2.67 rotations of the driver gear, the driven gear makes 1 rotation.

Step 3

9.2.1 The rotational frequency of the pulley on the washing machine

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Answer

The rotational frequency of the driven pulley can be derived using the gearbox ratio:

N1×D1=N2×D2N_1 \times D_1 = N_2 \times D_2
Where:

  • N1N_1 = Rotational frequency of washing machine pulley
  • D1D_1 = Diameter of washing machine pulley = 600 mm
  • N2N_2 = Rotational frequency of driven pulley = 7.2 r.s-1
  • D2D_2 = Diameter of driven pulley = 800 mm

Rearranging the equation yields:

N1=N2×D2D1=7.2×800600=9.6r.s1N_1 = \frac{N_2 \times D_2}{D_1} = \frac{7.2 \times 800}{600} = 9.6 r.s-1

Step 4

9.2.2 The power that can be transmitted

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Answer

To find the power transmitted, we can use the formula:

P=(T1T2)×FP = (T_1 - T_2) \times F
Where:

  • T1T_1 = Force in tight side of the belt = 300 N
  • T2T_2 = Tension in the slack side of the belt = 120 N
  • FF = Factor of rotation = 7.2

From the tension values, calculating gives:

P=(300120)×7.2=1296WattP = (300 - 120) \times 7.2 = 1296 Watt
This shows the power that can be transmitted by the pulley system.

Step 5

9.3 How can the volume of a certain mass of gas be changed?

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Answer

The volume of a certain mass of gas can be changed through its pressure and temperature. Adjusting these two variables allows for expansion or compression, changing the volume of the gas while keeping the mass constant.

Step 6

9.4 Define Boyle's law with reference to gases

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Answer

Boyle's law states that the volume of a given mass of gas is inversely proportional to the pressure exerted on it, provided the temperature remains constant. This means as the pressure increases, the volume decreases, and vice versa.

Step 7

9.5.1 The fluid pressure in the hydraulic system when in equilibrium

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Answer

The fluid pressure can be calculated using the area and the force applied:

P=FAP = \frac{F}{A}
Where:

  • FF = Applied load = 320 N
  • AA = Area of piston A = π(0.04m)2/4\pi (0.04 m)^2 / 4
    Calculating gives:

P=320AAP = \frac{320}{A_A}
Thus, the pressure in the hydraulic system is determined based on the area of piston A.

Step 8

9.5.2 The diameter of piston B

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Answer

To find the diameter of piston B, we start with:

PB=PAP_B = P_A
From the equilibrium of forces:

  • We know FB=FAF_B = F_A. Then use: A=FPA = \frac{F}{P}
    From the values of forces and pressure calculated, determine: DB=4ABπD_B = \sqrt{\frac{4A_B}{\pi}} This will yield the diameter of the piston B.

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