5.1 A spur gear with 118 teeth must be cut on a universal milling machine - NSC Mechanical Technology Welding and Metalwork - Question 5 - 2017 - Paper 1
Question 5
5.1 A spur gear with 118 teeth must be cut on a universal milling machine. Calculate the indexing required to cut this gear with the help of a Cincinnati dividing he... show full transcript
Worked Solution & Example Answer:5.1 A spur gear with 118 teeth must be cut on a universal milling machine - NSC Mechanical Technology Welding and Metalwork - Question 5 - 2017 - Paper 1
Step 1
A spur gear with 118 teeth must be cut on a universal milling machine. Calculate the indexing required to cut this gear with the help of a Cincinnati dividing head.
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Answer
To calculate the indexing required, we can use the formula:
Indexing=n40
where n is the number of teeth.
For a spur gear with 118 teeth:
Indexing=11840≈0.339
Thus, indexing will require approximately 0.339 units.
Step 2
Use simple line sketches to explain the difference between up-cut milling and down-cut milling on a milling machine. Indicate the work-piece feed and cutter rotation.
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Answer
Up-Cut Milling
In up-cut milling, the cutter rotates against the direction of the workpiece feed. As the cutter engages with the material, it starts from zero depth and increases to full depth. This process tends to push the workpiece upwards, resulting in less stability.
![Up-Cut Milling Diagram]
Down-Cut Milling
In down-cut milling, the cutter rotates in the same direction as the workpiece feed. The cutter begins at full depth and decreases to zero depth as it advances. This method gives a better surface finish and ensures higher stability by pulling the workpiece down.
![Down-Cut Milling Diagram]
Step 3
A tapered gib-head key must be made to fit a 102 mm diameter shaft. Calculate the following key dimensions:
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Answer
5.3.1 The width of the key:
Using the formula:
Width=4D=4102=25.5 mm
5.3.2 The thickness of the key:
Using the formula:
Thickness=6D=6102≈17 mm
5.3.3 The length of the key:
Using the formula:
Length=D×1.5=102×1.5=153 mm
5.3.4 The thickness of the key at the smaller end:
Using the formula:
Thickness at smaller end=100T×L=10017×153≈15.47 mm
Step 4
A spur gear has 60 teeth and a module of 3. Calculate the following in respect of the spur gear:
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