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7.1 Determine graphically (Bow's notation) the magnitude and nature of ALL the members of the framework in FIGURE 7.1 below - NSC Mechanical Technology Welding and Metalwork - Question 7 - 2018 - Paper 1

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7.1 Determine graphically (Bow's notation) the magnitude and nature of ALL the members of the framework in FIGURE 7.1 below. SCALE: Vector diagram 1 mm = 5 N FIGUR... show full transcript

Worked Solution & Example Answer:7.1 Determine graphically (Bow's notation) the magnitude and nature of ALL the members of the framework in FIGURE 7.1 below - NSC Mechanical Technology Welding and Metalwork - Question 7 - 2018 - Paper 1

Step 1

7.1 Determine graphically (Bow's notation) the magnitude and nature of ALL the members of the framework in FIGURE 7.1 below.

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Answer

To find the forces in the members graphically using Bow's notation, we can follow these steps:

  1. Drawing the Free Body Diagram (FBD): Start by sketching the FBD of the framework in Figure 7.1. Label the forces and angles clearly.

  2. Applying Equilibrium Conditions: Apply the static equilibrium conditions (sum of forces in the x and y directions, and moments about any point should be equal to zero).

  3. Vector Diagram: Use the given scale (1 mm = 5 N) to construct a vector diagram. Begin with one known force, and then successively add other forces beginning from the point where the known force acts.

  4. Determine Member Forces: From the vector diagram, measure the lengths of each member forces, converting them back into newtons using the scale. Determine the nature of each member (whether it is a strut or tie).

  5. Conclusion: Summarize your findings in a table showing the magnitude and nature of each member, using Bow's notation.

Step 2

7.2.1 Calculate the reactions at the supports RL and RR.

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Answer

To calculate the reactions at supports RL and RR:

  1. Select a Point: Choose point RR for moment calculation.

  2. Apply Moments about RR: RL×10=(8×8)+(4×5)+(6×2)RL \times 10 = (8 \times 8) + (4 \times 5) + (6 \times 2)

    • Calculate RL: RL = 9.6 kN.
  3. Apply Moments about RL: RR×10=(6×8)+(4×5)+(8×2)RR \times 10 = (6 \times 8) + (4 \times 5) + (8 \times 2)

    • Calculate RR: RR = 8.4 kN.

Step 3

7.2.2 Calculate the bending moments at points A, B, C, D and E.

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Answer

To find the bending moments:

  1. Using the Reaction Forces: Use the previously calculated reactions (RL and RR) to calculate moments around points A, B, C, D, and E.

  2. Calculate Each Moment:

    • At A: Moment = 0 kN.m.
    • At B: MB=RL×219.22 kN.m M_B = RL \times 2 - 19.2 \\ 2 \text{ kN.m}
    • At C: MC=RL×524kN.m M_C = RL \times 5 - 24 \\ kN.m
    • At D: MD=(RL×8)(4×6)(16.8)kN.m M_D = (RL \times 8) - (4 \times 6) - (16.8) \\ kN.m
    • At E: ME=RL×10(4×8)(6×2)0kN.m M_E = RL \times 10 - (4 \times 8) - (6 \times 2) \\ 0 kN.m

Step 4

7.2.3 Draw a bending moment diagram of the beam.

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Answer

To draw a bending moment diagram:

  1. Plot Points: Using the calculated bending moments for A, B, C, D, and E.
  2. Connect Points: Connect the points with straight lines, indicating regions of curvature where necessary (where the loading changes direction).
  3. Label the Diagram: Clearly label the diagrams with respective values and scales.

Step 5

7.3 Calculate the load that needs to be applied to a round stainless steel bar to cause a tensile stress of 80 MPa in the material. The diameter of the bar is 20 mm.

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Answer

To calculate the load:

  1. Calculate the Area: The cross-sectional area of the bar is given by: A=πd24=π(0.02)243.14×104m2A = \frac{\pi d^2}{4} = \frac{\pi (0.02)^2}{4} \approx 3.14 \times 10^{-4} \,m^2

  2. Using Stress Formula: The tensile stress formula is: Stress=LoadArea\text{Stress} = \frac{\text{Load}}{\text{Area}} Rearranging for load gives: Load=Stress×Area\text{Load} = \text{Stress} \times \text{Area} Load=80×106×3.14×10425,133 N\text{Load} = 80 \times 10^6 \times 3.14 \times 10^{-4} \approx 25,133 \text{ N}

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