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Vraag 7: KRAGTE 7.1 Vier kragte van 100 N, 200 N, 300 N en 400 N onderskeidelik werk op dieselfde punt in, soos in FIGUUR 7.1 hieronder getoon word - NSC Mechanical Technology Welding and Metalwork - Question 7 - 2017 - Paper 1

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Question 7

Vraag-7:-KRAGTE--7.1-Vier-kragte-van-100-N,-200-N,-300-N-en-400-N-onderskeidelik-werk-op-dieselfde-punt-in,-soos-in-FIGUUR-7.1-hieronder-getoon-word-NSC Mechanical Technology Welding and Metalwork-Question 7-2017-Paper 1.png

Vraag 7: KRAGTE 7.1 Vier kragte van 100 N, 200 N, 300 N en 400 N onderskeidelik werk op dieselfde punt in, soos in FIGUUR 7.1 hieronder getoon word. Bepaal, deur mi... show full transcript

Worked Solution & Example Answer:Vraag 7: KRAGTE 7.1 Vier kragte van 100 N, 200 N, 300 N en 400 N onderskeidelik werk op dieselfde punt in, soos in FIGUUR 7.1 hieronder getoon word - NSC Mechanical Technology Welding and Metalwork - Question 7 - 2017 - Paper 1

Step 1

Bepaal die resultant krag

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Answer

Om die resultant krag te bepaal, bereken ons die horisontale en vertikale komponente van die krachte. Die horisontale komponente is:

egin{align*} ext{Sum of Horizontal Forces (ΣH)} &= -200 ext{cos}(30°) + 300 - 400 \\ &= 192.4 N \\ ext{and} \\ ext{Sum of Vertical Forces (ΣV)} &= -100 + 200 ext{sin}(30°) + 300 ext{sin}(50°) - 100 \\ &= 229.81 N ext{Therefore, the resultant force} R = \\ R = \\ ext{sqrt}(ΣH^2 + ΣV^2) = \\ ext{sqrt}(192.4^2 + 229.81^2)

Die hoek van die resultant is: heta = ext{tan}^{-1} rac{229.81}{192.4} = 28.7° ext{ noord van oos}

Step 2

7.2.1 Spanning in die staaf

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Answer

Die spanning in die staaf kan bereken word deur die formule:

σ = rac{F}{A}

waar:

  • F = 40 kN = 40 000 N
  • A = rac{ ext{π}d^2}{4} = rac{ ext{π}(0.056)^2}{4} = 2.46 imes 10^{-3} m^2

Daarom, die spanning is:

σ = rac{40 000}{2.46 imes 10^{-3}} = 16.26 imes 10^6 ext{ Pa} = 16.26 ext{ MPa}

Step 3

7.2.2 Vormverandering

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Answer

Die vormverandering kan bereken word as:

ε = rac{σ}{E} \\ ext{waar E (Young's modulus) is 90 GPa = 90 imes 10^{9} Pa}

Substitusie gee:

ε = rac{16.26 imes 10^6}{90 imes 10^{9}} = 0.000180 ext{ m/m}

Step 4

7.2.3 Verandering in lengte

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Answer

Die verandering in lengte kan bereken word met die formule:

ΔL=εimesL0extwaarL0=0.85mΔL = ε imes L_0 \\ ext{waar} \\ L_0 = 0.85 m

Dus, die verandering in lengte:

ΔL=0.000180imes0.85=0.15extmmΔL = 0.000180 imes 0.85 = 0.15 ext{ mm}

Step 5

Bereken die reaksies in stut A en B

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Answer

Die reaksies kan bereken word deur die som van dieMomente om A en B te neem.

ext{R_A} + ext{R_B} = 960 imes 6 + 750 imes 8 \\ ext{R_A} = - ext{R_B} + 960 imes 6 + 750 imes 8 \ \

Bereken elke komponent as:

ext{R_B} = rac{6000+5760}{12} = 800N \\ ext{R_A} = 1030N \\

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