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6.1 Write down the meaning of the term reversible reaction - NSC Physical Sciences - Question 6 - 2023 - Paper 2

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6.1 Write down the meaning of the term reversible reaction. 6.2 State Le Chatelier's principle. 6.3 A change was made to the equilibrium mixture at t = 80 s. 6.3.... show full transcript

Worked Solution & Example Answer:6.1 Write down the meaning of the term reversible reaction - NSC Physical Sciences - Question 6 - 2023 - Paper 2

Step 1

Write down the meaning of the term reversible reaction.

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Answer

A reversible reaction is one where products can be converted back to reactants and vice versa. This means that both the forward and reverse reactions can occur, allowing the system to reach a state of equilibrium.

Step 2

State Le Chatelier's principle.

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Answer

Le Chatelier's principle states that when a system at equilibrium is subjected to a change in conditions (such as concentration, temperature, or pressure), the system will adjust itself to counteract that change and re-establish equilibrium.

Step 3

Write down the change made at t = 80 s.

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Answer

At t = 80 s, the concentration of A2(g) was increased, which means that more of A2(g) was added to the container.

Step 4

Use Le Chatelier's principle to explain how the system reacts to this change.

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Answer

According to Le Chatelier's principle, increasing the concentration of A2(g) will shift the equilibrium position to the right to favor the formation of products (B2(g) and AB(g)). This means that the system will attempt to consume some of the added A2(g) by producing more B2(g) and AB(g).

Step 5

Calculate the equilibrium constant, Kc, at t = 120 s.

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Answer

To calculate the equilibrium constant (Kc) at t = 120 s, we use the concentrations at equilibrium. If at this time, [A2] = 2 mol/dm³, [B2] = 2 mol/dm³, and [AB] = 8 mol/dm³, then:

Kc=[A2][B2][AB]2=(2)(2)(8)2=464=0.0625K_c = \frac{[A_2][B_2]}{[AB]^2} = \frac{(2)(2)}{(8)^2} = \frac{4}{64} = 0.0625

Step 6

Draw a potential energy diagram for this reaction.

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Answer

The potential energy diagram for this reaction would typically show the energy of the reactants at a certain level, then an activation energy peak for the transition state, followed by a lower energy level for the products, indicating that the reaction is exothermic. The diagram should clearly label the energy levels of the reactants, products, and the activation energy.

Step 7

Will the equilibrium constant, Kc, at 100 °C be GREATER THAN, LESS THAN or EQUAL TO the Kc at 150 °C? Explain the answer.

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Answer

The equilibrium constant, Kc, at 100 °C will generally be less than Kc at 150 °C if the reaction is exothermic. This is due to the fact that decreasing the temperature shifts the equilibrium position to favor the reactants. Therefore, as the temperature decreases, the value of Kc at the lower temperature will be less than that at a higher temperature.

Step 8

Describe the changes that will be observed on the graph between t = 0 s and t = 60 s.

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Answer

Between t = 0 s and t = 60 s, the graph shows increasing amounts of reactants and a gradual rise in products. The curve for reactants decreases as they are converted into products, while the product curves rise until they flatten out when equilibrium is reached. This indicates that the reaction is proceeding towards completion during this period.

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