9.1
'n Vereenvoudigde diagram van 'n GS elektriese motor word hieronder getoon - NSC Physical Sciences - Question 9 - 2023 - Paper 1
Question 9
9.1
'n Vereenvoudigde diagram van 'n GS elektriese motor word hieronder getoon.
9.1.1 Skryf die naam van komponent A neer.
9.1.2 Stel die energie-omsakeling ... show full transcript
Worked Solution & Example Answer:9.1
'n Vereenvoudigde diagram van 'n GS elektriese motor word hieronder getoon - NSC Physical Sciences - Question 9 - 2023 - Paper 1
Step 1
Skryf die naam van komponent A neer.
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Answer
Die naam van komponent A is die commutator.
Step 2
Stel die energie-omsakeling wat in die motor plaasvind.
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Die energie-omsakeling in die motor is van elektriese energie na meganiese energie.
Step 3
In watter rigting sal die spool draai? Kies uit KLOKSGEWYS of ANTI-KLOKSGEWYS.
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Die spool sal in 'n KLOKSGEWYS rigting draai.
Step 4
Noem TWEE veranderinge wat aan die motor gemaak kan word sodat die spool vinniger sal draai.
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Twee veranderinge wat gemaak kan word is: 1. Verhoog die sterkte van die magnetiese veld deur ster stronger magnets te gebruik. 2. Verhoog die aantal windings van die spoel.
Step 5
Definieer die term wortelgemiddeldewdraad-stroom.
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Die wortelgemiddeldewdraad-stroom is die wisselstroom (WS) wat dieselfde hoeveelheid energie/hewings effek as 'n ekwivalente gelykstroom (GS) het.
Step 6
Wanneer skakelaar S1 GESLUIT en skakelaar S2 OOP is, is die maksimum stroom deur die stroombaan 3,6 A.
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Answer
In hierdie geval is die maksimum stroom 3,6 A wanneer S1 geopen is en S2 gesluit.
Step 7
Bereken die wortelgemiddeldewdraad-stroom in die stroombaan.
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Die wortelgemiddeldewdraad-stroom, Irms, is bereken met die formule:
I_{rms} = rac{I_{max}}{ ext{√2}}
waar Imax=3.6A, dus I_{rms} = rac{3.6}{ ext{√2}} = 2.55 A.
