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2.1 A crate of mass 2 kg is being pulled to the right across a rough horizontal surface by a constant force F - NSC Physical Sciences - Question 2 - 2017 - Paper 1

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2.1 A crate of mass 2 kg is being pulled to the right across a rough horizontal surface by a constant force F. The force F is applied at an angle of 20° to the hori... show full transcript

Worked Solution & Example Answer:2.1 A crate of mass 2 kg is being pulled to the right across a rough horizontal surface by a constant force F - NSC Physical Sciences - Question 2 - 2017 - Paper 1

Step 1

Draw a labelled free-body diagram showing ALL the forces acting on the crate.

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Answer

To draw the free-body diagram, label the forces as follows:

  • Weight (W) of the crate downward, equal to the mass times the gravitational acceleration:
    W=mg=2extkgimes9.8extm/s2=19.6extNW = mg = 2 ext{ kg} imes 9.8 ext{ m/s}^2 = 19.6 ext{ N}
  • Normal Force (N) acting upward, vertically opposite to weight.
  • Friction Force (f) acting opposite to the direction of applied force F, given as 3 N.
  • Applied Force (F) has two components:
    1. Horizontal component (Fx=Fimesextcos(20°)F_x = F imes ext{cos}(20°))
    2. Vertical component (Fy=Fimesextsin(20°)F_y = F imes ext{sin}(20°))

The diagram should show these forces with arrows indicating their direction.

Step 2

Normal force acting on the crate.

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Answer

Using the equilibrium of forces in the vertical direction, we have: N+FyW=0N + F_y - W = 0 Substituting for Fy=Fimesextsin(20°)F_y = F imes ext{sin}(20°) and W=19.6extNW = 19.6 ext{ N}:

  1. Calculate FyF_y after finding F.
  2. Therefore: N=WFyN = W - F_y
  3. After substitution, you would assess based on the calculated FF.

Step 3

Force F.

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Answer

The applied force F can be calculated using the horizontal component and given friction force:
From the equation of motion: Fxf=maF_x - f = ma Substituting Fx=Fimesextcos(20°)F_x = F imes ext{cos}(20°), we get
Fimesextcos(20°)3=2imesaF imes ext{cos}(20°) - 3 = 2 imes a Using aa from 2.1.4 after completion.

Step 4

Acceleration of the crate.

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Answer

From the formula of force and using FF found in the previous step, we can find the acceleration: Fx=maF_x = ma Substituting the values and solving gives: a = rac{F_x - f}{m} Thus using FxF_x calculated, plug in values to find the acceleration.

Step 5

State Newton's Law of Universal Gravitation in words.

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Answer

Any two particles (objects) in the universe will attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Step 6

How does the magnitude of the gravitational force change?

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Answer

The gravitational force increases as the distance between the rock and the Earth decreases. This is based on the inverse square relationship in the law of gravitation, which states that as distance decreases, the force increases.

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