1.1 Which physical quantity is equal to the rate of change of momentum? A Mass B Impulse C Net force D Acceleration 1.2 The gravitational acceleration on the surface of a planet of radius R is g - NSC Physical Sciences - Question 1 - 2019 - Paper 1

To determine the gravitational acceleration at a height of 2R, we can use the formula for gravitational acceleration:

$g' = \frac{g}{(1 + \frac{h}{R})^2}$

where ( h ) is the height above the surface. In this case, ( h = 2R ): $g' = \frac{g}{(1 + 2)^2} = \frac{g}{9}$ Thus, the answer is B: ( g/9 ).

During the fall, the weight of the ball remains constant. This is because weight is defined as the gravitational force acting on the object, which depends on its mass and the gravitational acceleration. As the ball falls, neither of these factors changes, hence the weight remains constant.