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Blok A met 'n massa van m word verbind aan blok B, met 'n massa van 7,5 kg, deur 'n ligte onbrekbare tou wat oor 'n wrywingslose katrol beweeg - NSC Physical Sciences - Question 2 - 2023 - Paper 1
Question 2
Blok A met 'n massa van m word verbind aan blok B, met 'n massa van 7,5 kg, deur 'n ligte onbrekbare tou wat oor 'n wrywingslose katrol beweeg. Blok B word aanhangkl... show full transcript
Worked Solution & Example Answer:Blok A met 'n massa van m word verbind aan blok B, met 'n massa van 7,5 kg, deur 'n ligte onbrekbare tou wat oor 'n wrywingslose katrol beweeg - NSC Physical Sciences - Question 2 - 2023 - Paper 1
Step 1
2.1 Toon, deur middel van 'n berekening, dat die grootte van die versnellings van blok B 3,88 m·s² was terwyl die blok vertikaal afwards beweeg het.
Answer
To find the acceleration ( ext{a}) of block B, we can use the kinematic equation:
Where: v_f = final velocity = 3.41 , m/s v_i = initial velocity = 0 , m/s (when the block B is released) at = time taken.
Rearranging the equation gives: a = \frac{v_f - v_i}{t}
We need to find the time taken. The distance moved by block B is:
d = 1.5 , m \ (the height it falls)
Using the kinematic relation: d = v_i t + \frac{1}{2} a t^2
Substituting v_i = 0:
1.5 = \frac{1}{2} a t^2
From the initial kinematic equation we can estimate: a = \frac{v_f^2 - v_i^2}{2d} \rightarrow a = \frac{(3.41)^2 - 0}{2(1.5)} = 3.88 , m/s^2.
Thus, we have confirmed that the acceleration of block B is 3.88 m/s².
Step 2
2.2 Teken 'n benoemde vrye krachtsdiagram (vrye liggaamdiagram) en toon AL die kragte wat op blok B inwerk, onmiddellik nadat dit vrygelaat is.
Answer
In the free-body diagram for block B, we should account for the following forces:
-
Gravitational Force ( ext{F_g}) acting downward: where:
- (mass of block B)
- (acceleration due to gravity)
Hence, downwards.
-
Tension Force ( ext{T}) in the rope acting upward.
The resultant force ( ext{F}_{net}) on block B can be expressed as:
Using Newton's second law, we can relate it to acceleration:
Thus, we get:
3.88 m/s² = the calculated acceleration.
Step 3
2.3 Stel Newton se Tweede Bewingswet voor.
Answer
Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting upon it and inversely proportional to its mass. This can be expressed mathematically as:
where:
- is the net force acting on the object,
- is the mass of the object,
- is the acceleration of the object.
Step 4
2.4 Bereken die avontuur van die Newton se Tweede Wet op ELKE BLOK toe die pas terwyl hulle in beweging is.
Answer
For block A:
-
Gravitational Force: (assuming block A is m kg)
-
Tension Force in the rope will remain constant and we can assume the net force is: where we apply Newton's laws as specified previously.
For block B:
- Gravitational Force () is already calculated in the previous sections. Hence, apply accordingly for both blocks to maintain motion.
Step 5
2.5 Bereken die maksimum hoogte waardeur blok A bereik is.
Answer
The maximum height reached by block A can be determined using the energy conservation principle:
- Potential Energy ( ext{PE}) at the maximum height must equal the initial Kinetic Energy plus any additional energy from the earlier state. Hence, using the known kinematic terms and setting:
2. Thus, using: 3. Plugging in all known parameters to compute the height achieved.