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3.1 Define the term melting point - NSC Physical Sciences - Question 3 - 2021 - Paper 2

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3.1 Define the term melting point. 3.2 Write down the general conclusion that can be made about the melting points of straight-chain alkanes. 3.3 Name the type of ... show full transcript

Worked Solution & Example Answer:3.1 Define the term melting point - NSC Physical Sciences - Question 3 - 2021 - Paper 2

Step 1

Define the term melting point.

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Answer

The melting point is defined as the temperature at which a solid becomes a liquid, indicating the point of equilibrium between the solid and liquid phases of a substance.

Step 2

Write down the general conclusion that can be made about the melting points of straight-chain alkanes.

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Answer

As the carbon chain length of straight-chain alkanes increases, the melting points tend to increase. This is due to the greater surface area and stronger Van der Waals forces that result from longer carbon chains.

Step 3

Name the type of Van der Waals forces between molecules of octane.

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Answer

The type of Van der Waals forces between molecules of octane is London dispersion forces.

Step 4

Write down the predominant phase of the following alkanes at -100 °C.

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Answer

3.4.1 Pentane: Solid 3.4.2 Octane: Solid

Step 5

Is the molecular mass of hexane GREATER THAN, LESS THAN or EQUAL to that of 2,2-dimethylbutane?

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Answer

The molecular mass of hexane is LESS THAN that of 2,2-dimethylbutane.

Step 6

Is the boiling point of 2,2-dimethylbutane HIGHER THAN or EQUAL TO that of hexane?

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Answer

The boiling point of 2,2-dimethylbutane is LOWER THAN that of hexane.

Step 7

Fully explain the answer to QUESTION 3.5.2.

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Answer

2,2-dimethylbutane is more branched compared to hexane, leading to a smaller surface area and weaker intermolecular forces. As a result, less energy is required to overcome these forces, resulting in a lower boiling point.

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