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A group of students investigates the relationship between the work function of different metals and the maximum kinetic energy of the ejected electrons when the metals are irradiated with light of suitable frequency - NSC Physical Sciences - Question 11 - 2018 - Paper 1

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A group of students investigates the relationship between the work function of different metals and the maximum kinetic energy of the ejected electrons when the meta... show full transcript

Worked Solution & Example Answer:A group of students investigates the relationship between the work function of different metals and the maximum kinetic energy of the ejected electrons when the metals are irradiated with light of suitable frequency - NSC Physical Sciences - Question 11 - 2018 - Paper 1

Step 1

Define the term work function.

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Answer

The work function of a metal is defined as the minimum energy required to eject an electron from the surface of the metal.

Step 2

Write down the dependent variable for this investigation.

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Answer

The dependent variable is the maximum kinetic energy of the ejected electrons.

Step 3

Write down ONE control variable for this investigation.

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Answer

One control variable could be the wavelength of the ultraviolet light used during the investigation.

Step 4

Using the information in the table, and without any calculation, identify the metal with the largest work function. Explain the answer.

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Answer

The metal with the largest work function is Silver. This is because it has the smallest maximum kinetic energy (9.19 x 10^{18} J) compared to Lead (9.28 x 10^{18} J) and Potassium (9.58 x 10^{18} J). A higher work function indicates that more energy is required to eject electrons.

Step 5

Use information in the table to calculate the work function of potassium.

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Answer

Using the photoelectric equation, we have:

Ek(max)=hfW0E_k(max) = hf - W_0

Where:

  • Ek(max)=9.58imes1018extJE_k(max) = 9.58 imes 10^{18} ext{ J} for potassium
  • hh (Planck's constant) = 6.63imes1034extJs6.63 imes 10^{-34} ext{ Js}
  • ff (frequency) can be calculated from the wavelength λ=2imes108m\lambda = 2 imes 10^{-8} m, using c=fλc = f \lambda:

f=cλ=3×108extm/s2×108extm=1.5×1016extHzf = \frac{c}{\lambda} = \frac{3 \times 10^8 ext{ m/s}}{2 \times 10^{-8} ext{ m}} = 1.5 \times 10^{16} ext{ Hz}

Substituting into the equation:

W_0 = 9.945 \times 10^{-18} + 9.58 \times 10^{-18} = 1.95 \times 10^{-17} ext{ J} $$

Step 6

State how an increase in the intensity of the ultraviolet light affects the maximum kinetic energy of the photoelectrons.

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Answer

The maximum kinetic energy of the photoelectrons remains the same when the intensity of the ultraviolet light increases, assuming the frequency of the light stays constant.

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