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2.1 Write down the … 2.1.1 general formula for the homologous series to which compound B belongs - NSC Physical Sciences - Question 2 - 2016 - Paper 2

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2.1 Write down the … 2.1.1 general formula for the homologous series to which compound B belongs. 2.1.2 name of the homologous series to which compound D belongs. ... show full transcript

Worked Solution & Example Answer:2.1 Write down the … 2.1.1 general formula for the homologous series to which compound B belongs - NSC Physical Sciences - Question 2 - 2016 - Paper 2

Step 1

2.1.1 general formula for the homologous series to which compound B belongs.

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Answer

The general formula for the homologous series to which ethene (compound B) belongs is CnH2n, where n is the number of carbon atoms in the molecule.

Step 2

2.1.2 name of the homologous series to which compound D belongs.

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Answer

Compound D, which is an ester, belongs to the homologous series of carboxylic acids.

Step 3

2.1.3 letter of the compound that represents an aldehyde.

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Answer

The letter representing an aldehyde in the provided compounds is E, which corresponds to Methanal.

Step 4

2.2.1 Give a reason why compound B is classified as unsaturated.

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Answer

Compound B (Ethene) is classified as unsaturated because it contains a carbon-carbon double bond, which allows it to react with additional atoms or groups during chemical reactions.

Step 5

2.2.2 Classify the polymerisation as ADDITION or CONDENSATION.

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The polymerisation process of compound B is classified as ADDITION polymerisation since it involves the merging of monomer units without the loss of any molecule (such as water).

Step 6

2.2.3 Write down the CONDENSED STRUCTURAL FORMULA of the polymer.

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Answer

The condensed structural formula for the polymer formed from compound B is (C2H4)n, where 'n' represents the number of repeating units in the polymer chain.

Step 7

2.3.1 IUPAC name of compound C.

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The IUPAC name of compound C (2-bromo-4-methylhexane) is 2-bromo-4-methylhexane.

Step 8

2.3.2 IUPAC name of compound D.

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The IUPAC name of compound D (propyl propanoate) is propyl propanoate.

Step 9

2.4.1 STRUCTURAL FORMULA of compound F.

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Answer

The structural formula of compound F (C4H10O) can be represented as:

   H   H   H
   |   |   |
H--C--C--C--OH
   |   |   |
   H   H   H

Step 10

2.4.2 IUPAC NAME of a CHAIN ISOMER of compound F.

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A chain isomer of compound F can be named 2-butanol.

Step 11

2.5.1 IUPAC NAME of the carboxylic acid used.

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The IUPAC name of the carboxylic acid used is Propanoic acid.

Step 12

2.5.2 STRUCTURAL FORMULA of compound A.

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Answer

The structural formula of compound A (Propyl propanoate) can be represented as:

   O   H
   ||  | 
HO-C--C--C
   |   |  | 
   H   H  H

Step 13

2.6.1 Write down the MOLECULAR FORMULA of the product.

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Answer

The molecular formula of the product when compound B (Ethene) reacts with bromine (Br₂) is C2H4Br2.

Step 14

2.6.2 Use a calculation to determine the percentage composition of the product.

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Answer

To find the percentage composition of the product C2H4Br2:

  1. Calculate the molecular weight:

    • C: 12 x 2 = 24
    • H: 1 x 4 = 4
    • Br: 80 x 2 = 160
    • Total = 24 + 4 + 160 = 188
  2. Calculate the percentage of each element:

    • %C = (24/188) x 100 ≈ 12.77%
    • %H = (4/188) x 100 ≈ 2.13%
    • %Br = (160/188) x 100 ≈ 85.11%

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